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Effectus [21]
3 years ago
11

A carpenter charges $720 for 18 hours of work. She charges the same amount of money for each hour of work.

Mathematics
2 answers:
Alex3 years ago
7 0

Answer: A

Step-by-step explanation:

In A, they are adding 80 to each number if you go from 8, its 10; 400, 12; 480 14; 560 16; 640 18; 720 That would be the best answer!!

Rainbow [258]3 years ago
3 0

Answer:

A

Step-by-step explanation:

To start off, you know 18 hours= 720

So you could automatically get rid of B and D since 19 and 17 are not 18.

After that, you have it down to A and C. The way you would find how much she charges for one hour is dividing 720 by 18. When you do that it means you are divding 720$ into 18 different groups each group representing an hour. When you divide 720 by 18 you should get 40. So every hour she makes 40 dollars. 40x 2 hours is 80. I hope I helped you!

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negative

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Softa [21]

Answer:

  C and D

Step-by-step explanation:

Population density is the ratio of population to area. Its units are persons per square mile. Here, you're being asked to compare the population densities of several countries to the average population density in several US states.

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<h3>average</h3>

The idea of "average population density of the 10 states listed" is somewhat ambiguous. It could mean either of (a) the ratio of the total of the states' population to the total of their land area, or (b) the average of the population densities of the states. (In the attached, we computed both, but the answer remains the same using either number.)

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4 0
2 years ago
It's a question from real and complex numbers which I can't solve. so someone PLZ HeLp​
Semmy [17]

Answer:

\frac{1}{5}

Step-by-step explanation:

Using the rules of exponents

a^{m} × a^{n} = a^{(m+n)}, \frac{a^{m} }{a^{n} } = a^{(m-n)}, (a^m)^{n} = a^{mn}

Simplifying the product of the first 2 terms

\frac{a^{p^2+pq} }{a^{pq+q^2} } × \frac{a^{q^2+qr} }{a^{qr+r^2} }

= a^{p^2-q^2} × a^{q^2-r^2}

= a^{p^2-r^2}

Simplifying the third term

5((a^p+r)^{p-r}

= 5a^{(p+r)(p-r)} = 5a^{(p^2-r^2)}

Performing the division, that is

\frac{a^{(p^2-r^2)} }{5a^{(p^2-r^2)} } ← cancel a^{(p^2-r^2)} on numerator/ denominator leaves

= \frac{1}{5}

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