See the attached figure.
m ∠KAJ = 170° & m ∠LAM = 80°
We should know that :
m ∠KAJ + m ∠LAM + m ∠KAL + m ∠MAJ = 360°
∴ m ∠KAL + m ∠MAJ = 360° - (m ∠KAJ + m ∠LAM)
∴ m ∠KAL + m ∠MAJ = 360° - (170°+80°) = 360° - 250° = 110°
But : m ∠KAL = m ∠MAJ ⇒⇒⇒ <u>Opposite angles.</u>
∴ m ∠MAJ + m ∠MAJ = 110°
∴ 2 * m ∠MAJ = 110°
∴ m ∠MAJ = 110° ÷ 2 = 55°
<u>So, the answer is : m ∠MAJ = 55°</u>
Answer:
11/2
Step-by-step explanation:
6x−7=26
Step 1: Add 7 to both sides.
6x−7+7=26+7
6x=33
Step 2: Divide both sides by 6.
x= 11/2
Hey!
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We Know:
m∠AED = 34°
m∠EAD = 112°
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Solution:
You notice 4 small triangles in both triangles. That shows that both triangles are the same.
The angles are the same for m∠BDC and m∠AED.
The angles are the same for m∠ADB and m∠EAD
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Angles:
m∠BDC = 34°
m∠ADB = 112°
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Congruent Angles:
m∠AED ≡ m∠BDC
m∠EAD ≡ m∠ADB
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Hope This Helped! Good Luck!
Answer:
Step-by-step explanation:
From the information given,
Number of personnel sampled, n = 85
Mean or average = 6.5
Standard deviation of the sample = 1.7
We want to determine the confidence interval for the mean number of years that personnel spent in a particular job before being promoted.
For a 95% confidence interval, the confidence level is 1.96. This is the z value and it is determined from the normal distribution table. We will apply the following formula to determine the confidence interval.
z×standard deviation/√n
= 1.96 × 6.5/√85
= 1.38
The confidence interval for the mean number of years spent before promotion is
The lower end of the interval is 6.5 - 1.38 = 5.12 years
The upper end is 6.5 + 1.38 = 7.88 years
Therefore, with 95% confidence interval, the mean number of years spent before being promoted is between 5.12 years and 7.88 years
