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REY [17]
3 years ago
10

If a die is rolled one time find these probabilities of getting a 2

Mathematics
1 answer:
lapo4ka [179]3 years ago
8 0
1/6
the die has six sides 1,2,3,4,5,6
to get 2, you have one chance from 6
you get
1/6
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6 out of 24 employees at the water slides are temporary employees what percentage of the employees at the water slide are tempor
kykrilka [37]

Answer:

25%

Step-by-step explanation:

The question is:

6 is what percent of 24?

Set up the problem:

6            x

----   =   -----

24        100

600 / 24  =   25%

Check your answer:

25%   +   25%   +    25%    +  25%      =  100%

 6       +     6      +      6       +     6        =   24

3 0
3 years ago
The stock market dropped 220 points on Monday. It lost another 48 points on Tuesday, and on Wednesday, it gained 96 points. What
Leona [35]

Answer: 48 points gained in those 3 days.

Subtract 220 with 48, then add 96. Last step would be subtracting 220 with the amount they have now in those 3 days to find how much points the stock market gained in those 3 days.

Subtract 220-48.It‘ll be 172.

Add 172 with 96. 172+96=268.

Subtract 268 with how much points the stock market had 3 days ago. 268-220. So it would be about 48 points gained.

7 0
3 years ago
D) Vivek is 30 years younger than his father. After 10 years their ages will be in the ratio 1:2. Find their present ages.​
tangare [24]

Answer:

I think Vivek is 20 and his father is 50

Because 30 + 30 equals 60 as he has to be half his age he'll be 30 but that's in 10 years time. you just subtract 30 and 60 by 10 and you'll get 20 and 50

6 0
3 years ago
Read 2 more answers
If 10^2y = 25, then 10^-y equals:<br>(a) -1/5<br>(b) 1/625<br>(c) 1/50<br>(d) 1/25<br>(e) 1/5​
Gemiola [76]
<h3><u>given</u><u>:</u></h3>

<u>10 ^{2y}  = 25</u>

<h3><u>to</u><u> </u><u>find</u><u>:</u></h3>

<u>{10}^{y}  = .......</u>

<h3><u>solution</u><u>:</u></h3>

<u>10 ^{2y}  = 25</u>

<u>(10y {)}^{2}  =  {5}^{2}</u>

<u>10y = 5</u>

<u>\frac{1}{ {10}^{y} }  =  \frac{1}{5}</u>

<u>{10}^{ - y}  =  \frac{1}{5}</u>

<u>therefore</u><u>,</u><u> </u><u>the</u><u> </u><u>correct</u><u> </u><u>answer</u><u> </u><u>is</u><u> </u><u>option</u><u> </u><u>E</u><u>.</u>

8 0
2 years ago
Read 2 more answers
What are the real zeroes of x3 + 6 x2 – 9x - 54?
o-na [289]

Answer:

Option B 3,-3,-6 is correct.

Step-by-step explanation:

We need to find real zeroes of x^3+6x^2-9x-54

Solving

x^3+6x^2-9x-54\\=(x^3+6x^2)+(-9x-54)

Taking x^2 common from first 2 terms and -9 from last two terms we get

=(x^3+6x^2)+(-9x-54)\\=x^2(x+6)-9(x+6)\\

Taking (x+6) common

(x+6)(x^2-9)\\

x^2-9 can be solved using formula a^2-b^2 = (a+b)(a-b)

=(x+6)((x)^2-(3)^2)\\=(x+6)(x+3)(x-3)

Putting it equal to zero,

(x+6)(x+3)(x-3) =0\\x+6 =0, x+3=0\,\, and\,\, x-3=0\\x=-6, x=-3\,\, and\,\,  x=3

So, Option B 3,-3,-6 is correct.

7 0
3 years ago
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