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2 years ago

Someone help please thx in advance

Mathematics

1 answer:

Sedaia [141]2 years ago

7 0

Here’s the correct answer, how I got it, and something to help you for next time :)

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In ΔABC shown below, segment DE is parallel to segment AC: Triangles ABC and DBE where DE is parallel to AC The following two-co

storchak [24]

Answer:

3. BDE is congruent to BAC; corresponding angles postulate

4. B is congruent to B; reflexive property of equality

Step-by-step explanation:

I took the test.

5 0

2 years ago

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Solve for n.<br><br> n + 1 = 4(n – 8)<br> i will give a brainliest

yKpoI14uk [10]

n + 1 = 4(n - 8)

n + 1 = 4n - 32

n - 4n = -32 - 1

-3n = -33 / : (-3)

n = 11

6 0

2 years ago

nventing is a difficult way to make money. Only 5% of new patents earn a substantial profit. A certain city has just had30 indep

Arlecino [84]

Answer:

$P(X \geq 2) = 1-P(X$

And we can find the individual probabilities using the probability mass function and we got:

$P(X=0) = (30C0) (0.05)^0 (1-0.05)^{30-0} =0.2146$

$P(X=1) = (30C1) (0.05)^1 (1-0.05)^{30-1} = 0.3389$

And replacing we got:

$P(X \geq 2) = 1-P(X$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=30, p=0.05)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Solution to the problem

For this case we want this probability:

$P(X \geq 2)$

And we can use the complement rule and we got:

$P(X \geq 2) = 1-P(X$

And we can find the individual probabilities using the probability mass function and we got:

$P(X=0) = (30C0) (0.05)^0 (1-0.05)^{30-0} =0.2146$

$P(X=1) = (30C1) (0.05)^1 (1-0.05)^{30-1} = 0.3389$

And replacing we got:

$P(X \geq 2) = 1-P(X$

3 0

2 years ago

The question is below:

Sonja [21]

Answer:

x = 19.5, RQS=43

Step-by-step explanation:

It is important to note that RQS and TQS are supplementary, meaning their angles will add up to 180. Knowing this, we can create and solve the equation to find x..

(2x+4) + (6x+20) = 180

8x + 24 = 180

8x = 156

x = 19.5

Now that we know the value of x, we can substitute it into the equation for RQS, 2x+4.

2(19.5)+4

39+4

Hope this helped!

4 0

2 years ago

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<img src="https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%264%5C%5C8%26-5%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%

brilliants [131]

Answer:

What's this? I don't understand.

4 0

2 years ago

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