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3 years ago

I accidentally clicked the top answer which one is correct?! Please let me know!! Thank you!

Mathematics

2 answers:

scoray [572]3 years ago

7 0

Answer: B:

Step-by-step explanation: 7*6/7+4*6=30

42/7|4*6 also=30

geniusboy [140]3 years ago

5 0

Answer:

the first answer

Step-by-step explanation:

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Evaluate the expression for x=10.

zalisa [80]

Answer:

The answer is X - 10 = 0

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3 years ago

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If f(x) = 12x+2, then f^-1(x) =??

olga nikolaevna [1]

Step-by-step explanation:

Given

f(x) = 12x + 2

f^-1(x) = ?

Now

Let y = f(x)

or y = 12x + 2

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x = 12y + 2

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Therefore f^-1(x) = x - 2

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Table of value for y=2x^2+x

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values of x and y is (4, -2), (0, 0) and (2, 10)

Step-by-step explanation:

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2 years ago

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3 years ago

Which expression is equivalent to *picture attached*

DiKsa [7]

Answer:

The correct option is;

$4 \left (\dfrac{50 (50+1) (2\times 50+1)}{6} \right ) +3 \left (\dfrac{50(51) }{2} \right )$

Step-by-step explanation:

The given expression is presented as follows;

$\sum\limits _{n = 1}^{50}n\times \left (4\cdot n + 3 \right )$

Which can be expanded into the following form;

$\sum\limits _{n = 1}^{50} \left (4\cdot n^2 + 3 \cdot n\right ) = 4 \times \sum\limits _{n = 1}^{50} \left n^2 + 3 \times\sum\limits _{n = 1}^{50} n$

From which we have;

$\sum\limits _{k = 1}^{n} \left k^2 = \dfrac{n \times (n+1) \times(2n+1)}{6}$

$\sum\limits _{k = 1}^{n} \left k = \dfrac{n \times (n+1) }{2}$

Therefore, substituting the value of n = 50 we have;

$\sum\limits _{n = 1}^{50} \left k^2 = \dfrac{50 \times (50+1) \times(2\cdot 50+1)}{6}$

$\sum\limits _{k = 1}^{50} \left k = \dfrac{50 \times (50+1) }{2}$

Which gives;

$4 \times \sum\limits _{n = 1}^{50} \left n^2 = 4 \times \dfrac{n \times (n+1) \times(2n+1)}{6} = 4 \times \dfrac{50 \times (50+1) \times(2 \times 50+1)}{6}$

$3 \times\sum\limits _{n = 1}^{50} n = 3 \times \dfrac{n \times (n+1) }{2} = 3 \times \dfrac{50 \times (51) }{2}$

$\sum\limits _{n = 1}^{50}n\times \left (4\cdot n + 3 \right ) = 4 \times \dfrac{50 \times (50+1) \times(2\times 50+1)}{6} +3 \times \dfrac{50 \times (51) }{2}$

Therefore, we have;

$4 \left (\dfrac{50 (50+1) (2\times 50+1)}{6} \right ) +3 \left (\dfrac{50(51) }{2} \right )$ .

4 0

3 years ago