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Leno4ka [110]
3 years ago
6

I accidentally clicked the top answer which one is correct?! Please let me know!! Thank you!

Mathematics
2 answers:
scoray [572]3 years ago
7 0

Answer: B:

Step-by-step explanation: 7*6/7+4*6=30

42/7|4*6 also=30

geniusboy [140]3 years ago
5 0

Answer:

the first answer

Step-by-step explanation:

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Find the product of z1 and z2, where z1 = 7(cos 40° + i sin 40°) and z2 = 6(cos 145° + i sin 145°).
Oduvanchick [21]
For two complex numbers z_1=re^{i\theta}=r(\cos\theta+i\sin\theta) and z_2=se^{i\varphi}=s(\cos\varphi+i\sin\varphi), the product is

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That is, you multiply the moduli and add the arguments. You have z_1=7e^{i40^\circ} and z_2=6e^{i145^\circ}, so the product is

z_1z_2=7\times6(\cos(40^\circ+145^\circ)+i\sin(40^\circ+145^\circ)=42(\cos185^\circ+i\sin185^\circ)=42e^{i185^\circ}
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3 years ago
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To solve a system of inequalities so you can graph it how do you change these two equations into something like the two that are
Zigmanuir [339]
Explanation

Problem #2

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\begin{gathered} 3x-2y\leq4, \\ x+3y\leq6. \end{gathered}

(1) We solve for y the first inequality:

-2y\leq4-3x.

Now, we multiply both sides of the inequality by (-1), this changes the signs on both sides and inverts the inequality symbol:

\begin{gathered} 2y\ge-4+3x, \\ y\ge\frac{3}{2}x-2. \end{gathered}

The solution to this inequality is the set of all the points (x, y) over the line:

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This line has:

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,

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(2) We solve for y the second inequality:

\begin{gathered} x+3y\leq6, \\ 3y\leq6-x, \\ y\leq-\frac{1}{3}x+2. \end{gathered}

The solution to this inequality is the set of all the points (x, y) below the line:

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This line has:

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,

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(3) Plotting the lines of points (1) and (2), and painting the region:

• over the line from point (1),

,

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we get the following graph:

Answer

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8 0
1 year ago
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Annette [7]

Answer:1875cm^3

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3 years ago
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Answer:

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move the decimal 5 places to the right.

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