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EastWind [94]
3 years ago
15

*PLEASE FIND THE ANSWER QUICK!!!!!* Find the SA of this solid. please show the unit measure in your answer

Mathematics
1 answer:
omeli [17]3 years ago
3 0

Answer:

The SA of the rectangle is 270. The SA of both the triangles is 24

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The table below shows an inequality and a number by which to multiply both sides.
Paraphin [41]

Answer:

10>-15

Step-by-step explanation:

4 0
3 years ago
Use the table to determine the average rate of change from 3 to 6 storms
skelet666 [1.2K]

Answer:

Step-by-step explanation:

Good Morning If you can be more specific i can help you with this question but there is no table text me back if oyu still need help! ;)

5 0
3 years ago
2. A man buys eggs at 55kobo a score . he finds that 10% of the eggs are unsellable but sells the rest at 60kobo a dozen .find i
liubo4ka [24]

Answer:

Percentage Profit is 63.63%

Step-by-step explanation:

The man buys 440 eggs at 55 pence a score

i.e. he buys 20 eggs for 55 pence

He buys 1 egg for 55/20 = 2.75 pence

Therefore, he buys 440 eggs for = 440 × 2.75 = 1210 pence

10% eggs are unsaleable

thus he sold = 440 - 440 × 10/100 = 440 - 44 = 396 eggs

Eggs sold in dozen = 396/12 = 33

He sold 1 dozen for = 60 pence

Thus, he sold 33 dozen for = 33 × 60 = 1980 pence

Profit = 1980 - 1210 = 770 pence

% Profit = (770/1210) × 100 = 63.63%

(hope this helps can i plz have brainlist :D hehe)

3 0
3 years ago
Linda has a part-time job at the school. She makes between 44.00 and $51.00 a dayWhich is a reasonable estimate of the amount of
Luba_88 [7]

Answer:

$285

Step-by-step explanation:

The mode of 44 and 51 is 47.50 and 47.50 x 6 equals 285

6 0
3 years ago
Given the position of the particle, what the position(s) of the particle when it’s at rest
choli [55]

The position function of a particle is given by:

X\mleft(t\mright)=\frac{2}{3}t^3-\frac{9}{2}t^2-18t

The velocity function is the derivative of the position:

\begin{gathered} V(t)=\frac{2}{3}(3t^2)-\frac{9}{2}(2t)-18 \\ \text{Simplifying:} \\ V(t)=2t^2-9t-18 \end{gathered}

The particle will be at rest when the velocity is 0, thus we solve the equation:

2t^2-9t-18=0

The coefficients of this equation are: a = 2, b = -9, c = -18

Solve by using the formula:

t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}

Substituting:

\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}

We have two possible answers:

\begin{gathered} t=\frac{9+15}{4}=6 \\ t=\frac{9-15}{4}=-\frac{3}{2} \end{gathered}

We only accept the positive answer because the time cannot be negative.

Now calculate the position for t = 6:

undefined

6 0
1 year ago
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