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marshall27 [118]
3 years ago
8

The school that rob goes to is selling tickets to a spring musical. On the first day of ticket sales the school sold 22 senior c

itizen tickets and 10 child tickets for a total of $126. The school took in $51 on the second day by selling 3 senior citizen tickets and 9 child tickets. Find the price of a senior citizen ticket and the price of a child ticket.
Mathematics
1 answer:
Naddik [55]3 years ago
5 0

Answer: price of a senior citizen ticket = $3.71

Let the price of a child ticket = $4.43

Step-by-step explanation:

Let the price of a senior citizen ticket = x

Let the price of a child ticket = y

On the first day of ticket sales the school sold 22 senior citizen tickets and 10 child tickets for a total of $126. This will be:

22x + 10y = 126 ............ i

The school took in $51 on the second day by selling 3 senior citizen tickets and 9 child tickets. This will be:

3x + 9y = 51 ........... ii

22x + 10y = 126 ............ i

3x + 9y = 51 ........... ii

Multiply equation i by 3

Multiply equation ii by 22

66x + 30y = 378 ....... iii

66x + 198y = 1122 ........ iv

Subtract iii from iv

168y = 744

y = 744/168

y = 4.43

Since 3x + 9y = 51

3x + 9(4.43) = 51

3x + 39.87 = 51

3x = 51 - 39.87

3x = 11.13

x = 11.13/3

x = 3.71

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Can some one explain in an easy way pls
Helga [31]
What needs to be done first is to add up females and males that have passed.

42 + 14 = 56

so out of 56 students who passed 42 females passed 42/56 = 3/4 = 0.75

out of 56 students who passed, 14 males passed which turns into 14/56 = 1/4 = 0.25

check work; 0.75 + 0.25 = 1.00

NOW WE ARE DOING FAILS.

15 + 5 = 20

so out of 20 students who failed, 15 females failed so it turns into 15/20 = 3/4 = 0.75

out of 20 students who failed, 5 males failed. 5/20 = 1/4 = 0.25

check work; 0.75 + 0.25 = 1.00

i hope this helped! :)

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