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2 years ago

13

I NEED HELP PLEASE!!

2 answers:

Nimfa-mama [501]2 years ago

7 0

Answer:

f=15

Step-by-step explanation:

set 2.5 over 1 to make it a fraction and cross multiply

nadya68 [22]2 years ago

3 0

Yea it’s correct f=15

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How do i solve this question

frozen [14]

$\bf \begin{cases}
h(x)=(f\circ g)(x)\\
h(x)=\sqrt{x+5}\\
f(x)=\sqrt{x+2}
\end{cases}\\\\
-------------------------------\\\\
(f\circ g)(x)\implies f[\ g(x)\ ]\implies f[\ g(x)\ ]=\sqrt{g(x)+2}\qquad thus
\\\\\\
\sqrt{g(x)+2}=(f\circ g)(x)=h(x)=\sqrt{x+5}\qquad therefore
\\\\\\
\sqrt{g(x)+2}=\sqrt{x+5}\impliedby \textit{squaring both sides}\\\\\\
g(x)+2=x+5\implies g(x)=x+5-2\implies \boxed{g(x)=x+3}$

8 0

3 years ago

#4 find the value of x round answer to the nearest tenth

AnnyKZ [126]

Answer:

Step-by-step explanation:

Since this is a right angled triangle:

tan(∅) = opposite side/adjacent side

In this triangle:

tan(25°) = x/19

x = 8. 86 ≅ 8.9

6 0

3 years ago

Read 2 more answers

10 = 3x – 8<br><br> what is this

Margaret [11]

Answer:

<u><em>Answer is below</em></u>

Step-by-step explanation:

<u><em>10=3x-8</em></u>

<u><em>always remember to flip the equation</em></u>

<u><em>3x-8=10</em></u>

<u><em>Add 8 to both sides</em></u>

<u><em>3x-8(+8)=10(+8)</em></u>

<u><em>3x=18</em></u>

<u><em>Divide both sides by 3</em></u>

<u><em>3x/3=18/3</em></u>

<u><em>x=6</em></u>

8 0

3 years ago

Read 2 more answers

Ax-4y=-1. (6,1) find coefficient write complete equation

Rom4ik [11]

I think the answer is a=2

7 0

3 years ago

Find an equation of the sphere with center (2, −10, 3) and radius 5. $$25=(x−2)2+(y−(−10))2+(z−3)2 use an equation to describe i

lana66690 [7]

In the $x,y$ plane, we have $z=0$ everywhere. So in the equation of the sphere, we have

$25=(x-2)^2+(y+10)^2+(-3)^2\implies(x-2)^2+(y+10)^2=16=4^2$

which is a circle centered at (2, -10, 0) of radius 4.

In the $x,z$ plane, we have $y=0$ , which gives

$25=(x-2)^2+10^2+(z-3)^2\implies(x-2)^2+(z-3)^2=-75$

But any squared real quantity is positive, so there is no intersection between the sphere and this plane.

In the $y,z$ plane, $x=0$ , so

$25=(-2)^2+(y+10)^2+(z-3)^2\implies(y+10)^2+(z-3)^2=21=(\sqrt{21})^2$

which is a circle centered at (0, -10, 3) of radius $\sqrt{21}$ .

3 0

3 years ago