Please help me solve this problem
1 answer:
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The question is incomplete. Here is the complete question:
Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.95 probability that he will hit it. One day, Samir decides to attempt to hit 10 such targets in a row.
Assuming that Samir is equally likely to hit each of the 10 targets, what is the probability that he will miss at least one of them?
Answer:
40.13%
Step-by-step explanation:
Let 'A' be the event of not missing a target in 10 attempts.
Therefore, the complement of event 'A' is
Now, Samir is equally likely to hit each of the 10 targets. Therefore, probability of hitting each target each time is same and equal to 0.95.
Now,
We know that the sum of probability of an event and its complement is 1.
So,
Therefore, the probability of missing a target at least once in 10 attempts is 40.13%.
Answer:
2.Both boundary lines are solid.
3.A solution to the system is (1, 3)
5.The boundary lines intersect.
Step-by-step explanation:
we have
----> inequality A
The solution of the inequality A is the shaded area below the solid line
The slope of the solid line is 3
The point (1,3) is a solution of inequality A (lie in the shaded area of the solution set)
----> inequality B
The solution of the inequality B is the shaded area above the solid line
The slope of the solid line is -1
The point (1,3) is a solution of inequality B (lie in the shaded area of the solution set)
The solution of the system of inequalities is the shaded area between the two solids lines
see the attached figure
<u><em>Verify each statement</em></u>
1.The slope of one boundary line is 2
The statement is False
2.Both boundary lines are solid.
The statement is True
3.A solution to the system is (1, 3)
The statement is True
4.Both inequalities are shaded below the boundary lines
The statement is False
5.The boundary lines intersect.
The statement is True
The intersection point is (0.25,1.75)
see the attached figure
