2 years ago

Please help me solve this problem

Mathematics

1 answer:

algol [13]2 years ago

7 0

1.afgx2
2.bfgx2

I hope it helps Im really not that smart

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Write the following equation in the general form Ax + By + C = 0. 2x + y = 6

katen-ka-za [31]

2x + y = 6
2x + y - 6 = 0

answer is 2x + y - 6 = 0

hope that helps

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3 years ago

Tobeg says the equation 3x + 2y= 270 and y=4/5x + 20 intersect at the point (50,60) is this true how do you know

il63 [147K]

ANSWER

Yes it is very true

EXPLANATION

If the two equations intersect at $(50,60)$ then this point must satisfy the two equations.

$3x+2y=270---(1)$

We substitute $(50,60)$ in to erquation (1)

$3(50)+2(60)=270$

$150+120=270$

$270=270$

$y=\frac{4}{5}x+20 ---(2)$

We now substitute $(50,60)$ in to erquation (2) also

$60=\frac{4}{5}(50)+20$

$60=40+20$

$60=60$

Since the point satisfy all the two equations, it is true that they intersect at $(60,50)$

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3 years ago

Solve these equations. 1. -16 = v - 14 2. -2n = -22 3. 25 = b + 7

leonid [27]

1) -16 = v - 14

Add 14 to both sides.

v = -2

2) -2n = -22

Divide both sides by -2.

n = 11

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Subtract 7 from both sides.

b = 18

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It’s D bc Dt= 15x3 and it’s not that hard to solve

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Answer:

what's the question

Step-by-step explanation:

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