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maw [93]
4 years ago
13

DESPERATELY need help with #5 HELP

Mathematics
1 answer:
zloy xaker [14]4 years ago
3 0
One hour and thirty minutes
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(1+i/1-i)square root m
dsp73
M to the power 4 squared minus 23
4 0
3 years ago
Answer right or brainliest
Westkost [7]
Area of triangle:
1/2 • b • h = 1/2 • 12 • 6 = 36

Area of square:
l • w = 12 • 12 = 144

144 ÷ 36 = 4 squares
3 0
3 years ago
tickets to the theater cost $12 for adults and $9 for children. A group of 15 adults and children are attending the theater. If
kiruha [24]

Answer:

Can be either 6 adult tickets and 9 children tickets or 9 adult tickets and 5 children tickets

6 0
3 years ago
Read 2 more answers
Serena brought a total of 135 notebooks and pencils for her students. Each notebook cost 1.75 and each pencil cost 0.35. The tot
natima [27]

Answer:

81 pencils

Step-by-step explanation:

1. Set up variables

Pencils = p

notebooks= n

2. Set up a system of equations

p+n= 135                             (The amount of supplies bought)

1.75n +0.35p = 122.85       (Equation for the cost)

3. Solve the system of equations (I'll use substitution)

    a)p= 135-n  (I just rearranged it)

    1.75n + 0.35p= 122.85

     b) Substitute the first equation into the second)

    1.75n + 0.35(135-n) = 122.85

     c) Solve!

    1.75n + 47.25 - 0.35n = 122.85

    1.4n = 75.6

     n= 54

Serena bought 54 notebooks!

4. Substitute the number of notebooks into the first equation

p +n = 135

p + 54= 135

p = 81

Serena bought 81 pencils!!!

I hope this helps!!!!

7 0
3 years ago
Read 2 more answers
a bacteria triples it’s original population in 25 hours (A=3A0). How big will it’s population be in 100 hours
Maru [420]

Answer:

81 times the original size

Step-by-step explanation:

AA0ktA=3A0=?=?=25hours=A0ekt

Substitute the values in the formula.

3A0=A0ek⋅25

Solve for k. Divide each side by A0.

3A0A0=e25k

Take the natural log of each side.

ln3=lne25k

Use the power property.

ln3=25klne

Simplify.

ln3=25k

Divide each side by 25.

ln325=k

Approximate the answer.

k≈0.044

We use this rate of growth to predict the number of bacteria there will be in 100 hours.

AA0ktA=3A0=?=ln325=100hours=A0ekt

Substitute in the values.

A=A0eln325⋅100

Evaluate.

A=81A0

At this rate of growth, we can expect the population to be 81 times as large as the original population.

7 0
3 years ago
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