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sasho [114]
3 years ago
12

-2(6+s)>-15-2s Please answer!!

Mathematics
2 answers:
Lisa [10]3 years ago
7 0
<span>-2(6+s)>-15-2s

First step is to distribute. Multiply -2 by everything inside the parentheses.
-12 - 2s > -15 - 2s

Now add 2s to both sides.
-12 > -15 

Now divide both sides by -1, and remember to switch the sign because you divided by a negative number.
12 < 15

This has infinite solutions. </span>
valkas [14]3 years ago
6 0
This problem has infinitly many solutions
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Mani,James, and Isidro shared 1/2 of a pie. Which fraction of the whole pie did each of them receive?
bija089 [108]

Answer:

1/6

Step-by-step explanation:

\frac{1}{2}/3= 1/6

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3 years ago
A ladder 15 feet long leans against the top of a structure at a 60 degree angle to the ground. What is the height of the buildin
Goshia [24]

Answer:

height of the building is 12.99 feet.

Step-by-step explanation:

given, try to analyse:

  • ladder 15 feet long.
  • 60 degree angle to the ground.

the height of the building is opposite to the angle 60° and given hypotenuse, the ladder of 15 feet long.

using sine rule:

sin(x) = \frac{opposite}{hypotenuse}

sin(60) = \frac{opposite}{15}

opposite = sin(60) *15

opposite = 12.99feet

Therefore the height of the building is 12.99 feet.

7 0
2 years ago
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PLZ HELP ASAP !!! MARKIN BRAINIEST !!!
vovikov84 [41]

Answer:

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Step-by-step explanation:

4 0
4 years ago
A high school senior applies for admission to college A and to college B. He estimates that the probability of his being admitte
Fiesta28 [93]

The probability that he will be rejected to at least one of the colleges is 0.51.

Given probability that he will admit in A is 0.7, probability that he will not be admit in B is 0.5, probability that atleast one of his applications got rejected is 0.6.

We have to find the probability that he will be rejected to at least one of the colleges.

Probability that he will admit in A =0.7

Probability that he will not admit in A=1-0.7=0.3

Probability that he will not admit in B =0.5

Probability that he will admit in B=1-0.5=0.5

Probability  that he will be rejected to at least one of the colleges=probability that he will admit in A* probability that he will not admit in B+ probability that he will admit in B* probability that he will not admit in A+ probability that he will not admit in A* probability that he will not admit in B

=0.7*0.5+0.5*0.3+0.5*0.3

=0.35+0.15+0.15

=0.51

Hence the probability that he will be rejected to at least one of the colleges is 0.51.

Learn more about probability at brainly.com/question/24756209

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4 0
2 years ago
Suppose that 11% of all steel shafts produced by a certain process are nonconforming but can be reworked (rather than having to
attashe74 [19]

Answer:

0.9726 = 97.26% approximate probability that X is at most 30

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

11% of all steel shafts produced by a certain process are nonconforming but can be reworked (rather than having to be scrapped).

This means that p = 0.11

Random sample of 200 shafts

This means that n = 200

Mean and Standard deviation:

\mu = E(x) = np = 200*0.11 = 22

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{200*0.11*0.89} = 4.42

(a) What is the (approximate) probability that X is at most 30

Using continuity correction, this is P(X \leq 30 + 0.5) = P(X \leq 30.5), which is the pvalue of Z when X = 30.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{30.5 - 22}{4.42}

Z = 1.92

Z = 1.92 has a pvalue of 0.9726.

0.9726 = 97.26% approximate probability that X is at most 30

8 0
3 years ago
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