1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
likoan [24]
3 years ago
8

Triangle DEF has coordinates D(6, 4),

Mathematics
1 answer:
natta225 [31]3 years ago
7 0

Answer:

D = (6, -4)

E = (2, 1)

F = (-3, -5)

x-axis makes the y coordinate negative

You might be interested in
Somebody... PLEASE help<br><br> What is the only solution of 2x2 + 8x = x2 – 16?
makvit [3.9K]

Answer:

x= - 4

Step-by-step explanation:

2 * x^2 + 8 * x = x^2 - 16

2 * x^2 - x^2 + 8 * x + 16 = 0

x^2 + 8 * x + 16 = 0

(x + 4) * (x + 4) = 0

x = - 4

7 0
2 years ago
The number of accidents on a certain section of I-40 averages 4 accidents per weekday independent across weekdays. Assuming the
AysviL [449]

Answer:

1.83% probability there are no car accidents on that stretch on Monday

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

The number of accidents on a certain section of I-40 averages 4 accidents per weekday independent across weekdays.

This means that \mu = 4

What is the probability there are no car accidents on that stretch on Monday?

This is P(X = 0).

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-4}*(4)^{0}}{(0)!} = 0.0183

1.83% probability there are no car accidents on that stretch on Monday

5 0
3 years ago
What is 105,159 rounded to the nearest ten thousand
ludmilkaskok [199]
The answer will be 100,000 I hoped this helped;)
3 0
3 years ago
Read 2 more answers
Calculate the flux of the vector field F⃗ (x,y,z)=(exy+9z+4)i⃗ +(exy+4z+9)j⃗ +(9z+exy)k⃗ through the square of side length 3 wit
ikadub [295]

The square (call it S) has one vertex at the origin (0, 0, 0) and one edge on the y-axis, which tells us another vertex is (0, 3, 0). The normal vector to the plane is \vec n=\vec\imath-\vec k, which is enough information to figure out the equation of the plane containing S:

(x\,\vec\imath+y\,\vec\jmath+z\,\vec k)\cdot(\vec\imath-\vec k)=0\implies x-z=0\implies z=x

We can parameterize this surface by

\vec s(x,y)=x\,\vec\imath+y\,\vec\jmath+x\,\vec k

for 0\le x\le\frac3{\sqrt2} and 0\le y\le3. Then the flux of \vec F, assumed to be

\vec F(x,y,z)=(e^{xy}+9z+4)\,\vec\imath+(e^{xy}+4z+9)\,\vec\jmath+(9ze^{xy})\,\vec k,

is

\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\iint_S\vec F(\vec s(x,y))\cdot\vec n\,\mathrm dx\,\mathrm dy

=\displaystyle\int_0^3\int_0^{3/\sqrt2}\left((4+e^{xy}+9x)\,\vec\imath+(9+e^{xy}+4x)\,\vec\jmath+(e^{xy}+9x)\,\vec k\right)\cdot(\vec\imath-\vec k)\,\mathrm dx\,\mathrm dy

=\displaystyle\int_0^3\int_0^{3/\sqrt2}4\,\mathrm dx\,\mathrm dy=\boxed{18\sqrt2}

3 0
3 years ago
Which of these graphs represents an even function?
lidiya [134]
D because I’ve done this test before
6 0
2 years ago
Other questions:
  • I NEED HELPPPP
    6·1 answer
  • The length of a rectangle is 5 less than twice its width. Find the perimeter of this rectangle if its area is 273 yd2
    11·1 answer
  • For the function, f(x)=2x+1, which outputs match the inputs​
    10·1 answer
  • Can someone please help with this? the question is in the picture.
    15·2 answers
  • What come after 5,11,23,41,65,95,131 --- i will give brainly and points and thank you
    7·2 answers
  • What is eight times 28 equals??
    15·2 answers
  • How to solve this inequality: 3p - 6 &gt; 21.
    8·1 answer
  • Give an example of a line that is parallel to y=3x-4
    15·1 answer
  • How is 4.209 written using words? plz plz plz
    8·2 answers
  • Prove that (vectors)
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!