All categories

3 years ago

How many chicks hiding? Explain how you know.

Mathematics

1 answer:

Salsk061 [2.6K]3 years ago

8 0

You can’t really answer this without showing us the the answer you got from item 6

You might be interested in

If a fire is burning a building and it takes 2 hours to put it out using 2000 gal./min., what minimum diameter cylindrical tank

strojnjashka [21]

Answer:

The minimum diameter of the cylindrical tank needed to store the quantity needed to put out the fire is approximately 58.415 feet.

Step-by-step explanation:

A gallon equals 0.134 cubic feet. First, we determine the amount of water ( $Q$ ), measured in cubic feet, needed to put out the fire under the assumption that water is consumed at constant rate:

$Q = \dot Q \cdot \Delta t$ (1)

Where:

$\dot Q$ - Volume rate, measured in feet per minute.

$\Delta t$ - Time, measured in minutes.

If we know that $\dot Q = 2000\,\frac{gal}{min}$ and $\Delta t = 120\,min$ , then the amount of water is:

$Q = \left(2000\,\frac{gal}{min} \right)\cdot (120\,min) \cdot \left(0.134\,\frac{ft^{3}}{gal} \right)$

$Q = 32160\,ft^{3}$

And the diameter of the cylindrical tank based on the capacity found above is determined by volume formula for a cylinder:

$Q = \frac{\pi}{4}\cdot D^{2}\cdot h$ (2)

Where:

$D$ - Diameter, measured in feet.

$h$ - Height, measured in feet.

If we know that $Q = 32160\,ft^{3}$ and $h = 12\,ft$ , then the minimum diameter is:

$D^{2} = \frac{4\cdot Q}{\pi\cdot h}$

$D = 2\cdot \sqrt{\frac{Q}{\pi\cdot h} }$

$D = 2\cdot \sqrt{\frac{32160\,ft^{3}}{\pi\cdot (12\,ft)} }$

$D \approx 58.415\,ft$

The minimum diameter of the cylindrical tank needed to store the quantity needed to put out the fire is approximately 58.415 feet.

8 0

3 years ago

What is 2/5 times -10

maxonik [38]

Answer:

-4

Step-by-step explanation:

2/5 times -10 = -4

6 0

3 years ago

Read 2 more answers

find the midpoint of the line segment whose endpoints are (-2, 5) and (4, -9). (2, -7) (1, -4) (1, -2)

Alex_Xolod [135]

M(x, y) = ((x1 + x2)/2, (y1 + y2)/2) = ((-2 + 4)/2, (5 - 9)/2) = (2/2, -4/2) = (1, -2)

7 0

3 years ago

Read 2 more answers

Which equation could represent a circle with a center located at (11,-5)

Anon25 [30]

The standard equation of a circle is:

$(x-h)^2-(y-k)^2=r^2$ where (h,k) is the center and r is the radius.

We need to make an equation of a circle, whose center is (11,-5) with any radius. Therefore, substitute the value.

$(x-h)^2-(y-k)^2=r^2 \\ (11,-5)=(h,k) \\ (x-11)^2-(y-5)^2=64$

The bolded part is your answer. Since the radius is not given, we can put any value.

6 0

3 years ago

Correctly describe the slope of the graph of 2x + 5y = 6?

USPshnik [31]

Answer:

$2x + 5y = 6z$

6 0

3 years ago