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Allushta [10]
3 years ago
15

Help please someone ans

Mathematics
1 answer:
babymother [125]3 years ago
3 0

Answer:

40

Step-by-step explanation:

the line in the middle shows the median

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A recipe take 90 minutes to make.25% of the time is spent preparing the ingredients.How many minutes are spent preparing
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It will take 22.5 min cause 25 divided by 100 wuld be 4 wich then divide 90 with
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3 years ago
Solve. If this is no solution write s { }<br> 5x-9&gt;8+5x
german
The answer is there are no solution
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3 years ago
Calculus Problem
Roman55 [17]

The two parabolas intersect for

8-x^2 = x^2 \implies 2x^2 = 8 \implies x^2 = 4 \implies x=\pm2

and so the base of each solid is the set

B = \left\{(x,y) \,:\, -2\le x\le2 \text{ and } x^2 \le y \le 8-x^2\right\}

The side length of each cross section that coincides with B is equal to the vertical distance between the two parabolas, |x^2-(8-x^2)| = 2|x^2-4|. But since -2 ≤ x ≤ 2, this reduces to 2(x^2-4).

a. Square cross sections will contribute a volume of

\left(2(x^2-4)\right)^2 \, \Delta x = 4(x^2-4)^2 \, \Delta x

where ∆x is the thickness of the section. Then the volume would be

\displaystyle \int_{-2}^2 4(x^2-4)^2 \, dx = 8 \int_0^2 (x^2-4)^2 \, dx \\\\ = 8 \int_0^2 (x^4-8x^2+16) \, dx \\\\ = 8 \left(\frac{2^5}5 - \frac{8\times2^3}3 + 16\times2\right) = \boxed{\frac{2048}{15}}

where we take advantage of symmetry in the first line.

b. For a semicircle, the side length we found earlier corresponds to diameter. Each semicircular cross section will contribute a volume of

\dfrac\pi8 \left(2(x^2-4)\right)^2 \, \Delta x = \dfrac\pi2 (x^2-4)^2 \, \Delta x

We end up with the same integral as before except for the leading constant:

\displaystyle \int_{-2}^2 \frac\pi2 (x^2-4)^2 \, dx = \pi \int_0^2 (x^2-4)^2 \, dx

Using the result of part (a), the volume is

\displaystyle \frac\pi8 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{256\pi}{15}}}

c. An equilateral triangle with side length s has area √3/4 s², hence the volume of a given section is

\dfrac{\sqrt3}4 \left(2(x^2-4)\right)^2 \, \Delta x = \sqrt3 (x^2-4)^2 \, \Delta x

and using the result of part (a) again, the volume is

\displaystyle \int_{-2}^2 \sqrt 3(x^2-4)^2 \, dx = \frac{\sqrt3}4 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{512}{5\sqrt3}}

7 0
2 years ago
Plzzz helpppppp nowwwww
snow_lady [41]

Answer:

x= 10

I hope i helped, best of luck!

4 0
2 years ago
Read 2 more answers
What is the slope of the point (1÷4,3÷2)and (-1,-3)​
Viefleur [7K]

Step-by-step explanation:<u>The slope calculator helps find the slope of any line through two given ... the slope of the line passing through the points (3,8) and (-2, 10) . ... A 1/20 slope is one that rises by 1 unit for every 20 units traversed horizontally.</u>

<u />

3 0
3 years ago
Read 2 more answers
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