Answer:
3 3/11
Step-by-step explanation:
2x+4(2x+7)+3(2x+4)
2x+8x+28+6x+12
16x+40
16x+40 would be the answer you can’t solve it any further
You have to subtract $40 from $68 make sure the larger number is in the front. If you did that all you would get $28.
Answer:
see below
Step-by-step explanation:
Eric will drive between 70 -4 = 66 mph and 70+4 = 74 mph. He will <em>not</em> drive less than 66 or more than 74 mph.
We know the width of the rectangle in the middle of the trapezoid is 24 (from the top of the image), so we can subtract that from the bottom width of the trapezoid to get the combined length of the bottom of both triangles.

Since this is an isosceles trapezoid, both triangle bases are the same length, so we can cut this value in half to get the length of
and 

Finally, we can use the Pythagorean Theorem to find the length of
:




