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artcher [175]
3 years ago
14

I need help on question 7

Mathematics
2 answers:
NNADVOKAT [17]3 years ago
7 0
Try 30 % i think that is correct
just olya [345]3 years ago
7 0
ANNEL TOTAL PAY $13.30 
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scoundrel [369]

Use this word problem just change the numbers

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How do you do a ratio tape diagram
sp2606 [1]
15 degrees hope this helps mark as brainliest
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3 years ago
A bank in the Bay area is considering a training program for its staff. The probability that a new training program will increas
WITCHER [35]

Answer:

P(B' \cup A') = P((A \cap B)') = 1-P(A \cap B)= 1-0.32=0.68

See explanation below.

Step-by-step explanation:

For this case we define first some notation:

A= A new training program will increase customer satisfaction ratings

B= The training program can be kept within the original budget allocation

And for these two events we have defined the following probabilities

P(A) = 0.8, P(B) = 0.2

We are assuming that the two events are independent so then we have the following propert:

P(A \cap B ) = P(A) * P(B)

And we want to find the probability that the cost of the training program is not kept within budget or the training program will not increase the customer ratings so then if we use symbols we want to find:

P(B' \cup A')

And using the De Morgan laws we know that:

(A \cap B)' = A' \cup B'

So then we can write the probability like this:

P(B' \cup A') = P((A \cap B)')

And using the complement rule we can do this:

P(B' \cup A') = P((A \cap B)')= 1-P(A \cap B)

Since A and B are independent we have:

P(A \cap B )=P(A)*P(B) =(0.8*0.4) =0.32

And then our final answer would be:

P(B' \cup A') = P((A \cap B)') = 1-P(A \cap B)= 1-0.32=0.68

5 0
3 years ago
What is the solution to the system of equations graphed below? y = –4x + 33
satela [25.4K]

y = –4x + 33

y-33 = –4x

y-33/4 = x

X=y-33/4.

5 0
3 years ago
Read 2 more answers
Is the work shown below correct? Explain your answer.
riadik2000 [5.3K]
(11 + 21) - ( 3 - 100 )
= 32 + 97
= 129

or (11+21)-(3+100)
= 32 - 103
= - 71


I have no idea about your topic but hope it's right! Good luck
8 0
3 years ago
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