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3 years ago

WHAT WOULD THIS BEEE!!

Mathematics

2 answers:

Yuliya22 [10]3 years ago

8 0

use Pythagoras theorem

20 units

qwelly [4]3 years ago

3 0

The answer is 20 units! (B)

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The table shows the time y (in minutes) it takes to make x burritos. A- graph B- how long does it take to fix 7 burritos

DedPeter [7]

Answer:

5.25 minutes

Step-by-step explanation:

7 * 0.75 = 5.25

5 0

3 years ago

HELP PLZZ

Arisa [49]

19.5 because 6 minus 5.5 is equal to 0.5 and if you just add 0.5 to 19.5 it will be 19.5

4 0

3 years ago

To make 5 pizzas, 1/2 cup of flour is used a. How much flour is needed to make one pizza? b.. How many cups of flour are needed

pogonyaev

Answer:

for a single pizza 1/10 a cup

for 12 pizzas 1 1/5 a cup

you can make 56 pizzas with 5 2/3 cups.

Step-by-step explanation:

for 5 pizzas you need 1/2 cup of flour, so to find out how much you'll need for a single pizza you'll need to divide it with 5. 1/2÷5=1/10

for a dozen pizzas you'll need to multiply that with 12. 1/10x12=12/10=1 1/5

Then to find out how many can we make with 5 2/3 cups we'll divide it with that 1/10

56/10÷1/10= 56 pizzas

8 0

3 years ago

The last time brea played softball she hit the ball 35 percent of the times she was at bat based on this information how many ti

WITCHER [35]

Answer:

The answer to your question is 7 times

Step-by-step explanation:

Data

Percent of accuracy = 35%

Times she is at bat = 20

Times she hit the ball = ?

Process

1.- Use proportions to solve this problem

20 times will be the 100% because is the total number of times she is at bat.

20 times ------------------ 100%

x ------------------ 35%

x = (35 x 20) / 100

x = 700 / 100

x = 7

2.- Conclusion

From 20 times she is at bat, she will hit the ball 7 times.

4 0

3 years ago

in exercises 15-20 find the vector component of u along a and the vecomponent of u orthogonal to a u=(2,1,1,2) a=(4,-4,2,-2)

Nimfa-mama [501]

Answer:

The component of $\vec u$ orthogonal to $\vec a$ is $\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)$ .

Step-by-step explanation:

Let $\vec u$ and $\vec a$ , from Linear Algebra we get that component of $\vec u$ parallel to $\vec a$ by using this formula:

$\vec u_{\parallel \,\vec a} = \frac{\vec u \bullet\vec a}{\|\vec a\|^{2}} \cdot \vec a$ (Eq. 1)

Where $\|\vec a\|$ is the norm of $\vec a$ , which is equal to $\|\vec a\| = \sqrt{\vec a\bullet \vec a}$ . (Eq. 2)

If we know that $\vec u =(2,1,1,2)$ and $\vec a=(4,-4,2,-2)$ , then we get that vector component of $\vec u$ parallel to $\vec a$ is:

$\vec u_{\parallel\,\vec a} = \left[\frac{(2)\cdot (4)+(1)\cdot (-4)+(1)\cdot (2)+(2)\cdot (-2)}{4^{2}+(-4)^{2}+2^{2}+(-2)^{2}} \right]\cdot (4,-4,2,-2)$

$\vec u_{\parallel\,\vec a} =\frac{1}{20}\cdot (4,-4,2,-2)$

$\vec u_{\parallel\,\vec a} =\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$

Lastly, we find the vector component of $\vec u$ orthogonal to $\vec a$ by applying this vector sum identity:

$\vec u_{\perp\,\vec a} = \vec u - \vec u_{\parallel\,\vec a}$ (Eq. 3)

If we get that $\vec u =(2,1,1,2)$ and $\vec u_{\parallel\,\vec a} =\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$ , the vector component of $\vec u$ is:

$\vec u_{\perp\,\vec a} = (2,1,1,2)-\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$

$\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)$

The component of $\vec u$ orthogonal to $\vec a$ is $\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)$ .

4 0

3 years ago