Question

Line segment AB has endpoints A(1,-3) and B(-2,1). What is the midpoint of line segment AB

Answer 1

Answer:

$\large\boxed{\left(-\dfrac{1}{2},\ -1\right)}$

Step-by-step explanation:

$\text{The formula of a midpoint:}\\\\\left(\dfrac{x_1+x_2}{2};\ \dfrac{y_1+y_2}{2}\right)\\\\================================\\\\A(1,\ -3),\ B(-2,\ 1)\\\\\text{Substitute:}\\\\x=\dfrac{1+(-2)}{2}=\dfrac{-1}{2}=-\dfrac{1}{2}\\\\y=\dfrac{-3+1}{2}=\dfrac{-2}{2}=-1$

Answer 2

Answer:

$(\frac{-1}{2} ,-1)$

Step-by-step explanation:

line segment AB has endpoints A(1,-3) and B(-2,1).

To find the midpoint of AB we use formula

$(\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )$

A(1,-3) is (x1,y1) , B(-2,1) is (x2,y2)

Plug in the values in the formula

$(\frac{1-2}{2} ,\frac{-3+1}{2} )$

$(\frac{-1}{2} ,\frac{-2}{2} )$

$(\frac{-1}{2} ,-1)$