Turn F(x) into vertex form:
y=x^2+8x+6
y-6=x^2+8x
y-6+16=x^2+8x+16
y+10=(x+4)^2
Thus the vertex is (-4,-10)
This is a minimum because the parabola is up up, or is positive
Answer:
(4,8), (24,8),and (12,16)
Step-by-step explanation:
When dilating I’m pretty sure you multiply each of the vertices by what your dilating which is 4, so multiply all of those by 4.
-45.6 is the answer if you evaluate