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3 years ago

Through (-6,4), slope:2

Mathematics

1 answer:

madreJ [45]3 years ago

5 0

Answer:

y - 4 = 2(x + 6)

Step-by-step explanation:

Use the point-slope formula y - k = m(x - h):

y - 4 = 2(x + 6)

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A vehicle factory manufactures cars. The unit cost (the cost in dollars to make each car) depends on the number of cars made. If

Nataly [62]

Answer:

The function is missing in the question. The function is $C(x) = 0.8x^2 -544x +97410$

The answer is 4930

Step-by-step explanation:

Unit cost of a car is given as

$C(x) = 0.8x^2 -544x +97410$

Cost will be minimum when

x = -(-544)/ 2 x 0.8

= 340

Therefore, minimum cost for unit car is

$C(x) = 0.8x^2 -544x +97410$

$= 0.8(340)^2 -544(340) +97410$

= 4930

4 0

3 years ago

Which of the following words is a proper noun?

kondor19780726 [428]

Answer:

apple

Step-by-step explanation:

apple

4 0

3 years ago

Read 2 more answers

(01.01) Evaluate −15 + (−4). (1 point) Group of answer choices

arsen [322]

Answer: -19

Step-by-step explanation: when ur adding two negatives it's gonna equal a negative

8 0

3 years ago

Read 2 more answers

If the present value of an item is P

Mumz [18]

Answer:

$50,000

Step-by-step explanation:

Formula to find interest :

I = Prt

Solving :

I = (20,000)(0.06)(25)
I = (1.5)(20,000)
I = (30,000)

Future value :

P + I
20,000 + 30,000
$50,000

4 0

2 years ago

The function g(x) = 12,500(0.91)x represents the value of a piece of farm equipment after x years. Approximately when will its v

topjm [15]

Answer:

B. 7.3 years

Step-by-step explanation:

The question is wrong. The correct function is :

$g(x)=12500(0.91)^{x}$

We have the function $g(x)$ that represents the value of a piece of farm equipment after $x$ years.

This means that when $x=0$ its original value is :

$g(0)=12500(0.91)^{0}=12500$

Now we want to calculate approximately when will its value be half its original value. Then, we write :

$\frac{12500}{2}=6250$

$6250$ is half of its original value. We need to find $x$ that satisfies the following equation :

$g(x)=6250=12500(0.91)^{x}$

Solving for $x$ :

$6250=12500(0.91)^{x}$ ⇒

$0.5=(0.91)^{x}$

Now we apply natural logarithm to each side of the equation :

$ln(0.5)=ln[(0.91)^{x}]$

Using logarithm properties :

$ln(0.5)=ln[(0.91)^{x}]$ ⇒

$ln(0.5)=x[ln(0.91)]$

$x=\frac{ln(0.5)}{ln(0.91)}$ ⇒

$x$ ≅ $7.3496$

The correct option is B. 7.3 years

4 0

3 years ago