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3 years ago

Plz help I’m not good with math!!

Mathematics

1 answer:

Westkost [7]3 years ago

8 0

Answer:

point slope, slope intercept form, and I think two point

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You earn money by washing windows at $14 per house or washing cars at $5 per car how many cars would you have to make the same a

Wewaii [24]

Answer:

Step-by-step explanation:

10•14=140

140/5=28

Hope this helps, have a great day/night!

5 0

3 years ago

Read 2 more answers

Help please and thanks will mark as brainliest

Paraphin [41]

11)

3x = 180
x = 60

12)
6x + 18 = 180
6x = 162
x = 27

8 0

3 years ago

Suppose that the speeds of cars travelling on California freeways are normally distributed with a mean of 61 miles/hour. The hig

cricket20 [7]

Answer:

The standard deviation of the speeds of cars travelling on California freeway is 6.0088 miles per hour.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

In this problem, we have that:

Suppose that the speeds of cars travelling on California freeways are normally distributed with a mean of 61 miles/hour. This means that $\mu = 61$ .

The highway patrol's policy is to issue tickets for cars with speeds exceeding 75 miles/hour. The records show that exactly 1% of the speeds exceed this limit. This means that the pvalue of Z when $X = 75$ is 0.99. This is $Z = 2.33$

$Z = \frac{X - \mu}{\sigma}$

$2.33 = \frac{75 - 61}{\sigma}$

$2.33\sigma = 14$

$\sigma = \frac{14}{2.33}$

$\sigma = 6.0088$

The standard deviation of the speeds of cars travelling on California freeway is 6.0088 miles per hour.

6 0

3 years ago

You pull a Queen (any of 4 suits) out of 52-card deck. I pull a pair of grey socks from the 12 -pair pack. There are 3 pairs of

nignag [31]

Answer: The probability of pulling a Queen has a smaller chance of happening.

Step-by-step explanation: In a 52-card deck, you have 4 Queens altogether belonging to each of the four suits. If you pull a card at random out of a complete pack, the probability of picking a Queen would be as follows;

P(Q) = Number of required outcomes/Number of all possible outcomes

P(Q) = 4/52

P(Q) = 1/13

P(Q) = 0.07692 or 7.69%

Also in a 12-pair pack of socks, you have 3 pairs with the color grey. The probability of picking a pair of grey socks at random is given as follows;

P(G) = Number of required outcomes/Number of all possible outcomes

P(G) = 3/12

P(G) = 1/4

P(G) = 0.25 or 25%

Therefore the probability of pulling a Queen has a 7.69% chance of happening and thats a lower chance.

4 0

4 years ago

I need help asap pleaseeee

lesantik [10]

Answer:

Step-by-step explanation:

401.92 divided by 16 = 25.12

25.12 divided by 3.14 is 8

3 0

3 years ago