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elena-14-01-66 [18.8K]
3 years ago
15

PLZZZZZ HELPPP ASAPPPP IM FREAKIN OUTTTTTT

Mathematics
1 answer:
Temka [501]3 years ago
3 0

Answer:

1. C)  2 (x-2)(x-1)

2. D) cannot be factored

3. B)  (x-8)(x+5)

4. D)  2 (x+5)(x-5)

5. D)  (x+5)(x-3)

hope this was helpful! let me know if you needd the steps! c:

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What is the greatest perfect square that is a factor of 392
Alexxx [7]

Answer:

The factor of 392 is 36.

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What has the same value as 4/7 ➗2? help me plssssssss
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If you do 4/7 divide by 2 the answer is 0.2857
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Which answer is the best explanation for how to check to see that the difference has been calculated correctly for this problem?
scoundrel [369]
A. No, because if you add 76.5 and 4.32, you'll get 80.82 instead of 72.18.

B. Yes, because if you add 72.18 and 4.32 you'll get 76.5

C. No, because if you substract 4.32 from 72.18, you'll get 67.86 instead of 76.5.

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4 0
3 years ago
What is the easiest way to solve a quadratic equation?​
algol [13]

Answer: This is an opinion, look below! :)

Step-by-step explanation:

Factor the expression. To factor the expression, you have to use the factors of the {\displaystyle x^{2}}x^{2} term (3), and the factors of the constant term (-4), to make them multiply and then add up to the middle term, (-11). Here's how you do it:

Since {\displaystyle 3x^{2}}3x^{2} only has one set of possible factors, {\displaystyle 3x}3x and {\displaystyle x}x, you can write those in the parenthesis: {\displaystyle (3x\pm ?)(x\pm ?)=0}(3x\pm ?)(x\pm ?)=0.

Then, use process of elimination to plug in the factors of 4 to find a combination that produces -11x when multiplied. You can either use a combination of 4 and 1, or 2 and 2, since both of those numbers multiply to get 4. Just remember that one of the terms should be negative, since the term is -4.[3]

By trial and error, try out this combination of factors {\displaystyle (3x+1)(x-4)}(3x+1)(x-4). When you multiply them out, you get {\displaystyle 3x^{2}-12x+x-4}3x^{2}-12x+x-4. If you combine the terms {\displaystyle -12x}-12x and {\displaystyle x}x, you get {\displaystyle -11x}-11x, which is the middle term you were aiming for. You have just factored the quadratic equation.

As an example of trial and error, let's try checking a factoring combination for {\displaystyle 3x^{2}-11x-4=0}3x^{2}-11x-4=0 that is an error (does not work): {\displaystyle (3x-2)(x+2)}(3x-2)(x+2) = {\displaystyle 3x^{2}+6x-2x-4}3x^{2}+6x-2x-4. If you combine those terms, you get {\displaystyle 3x^{2}-4x-4}3x^{2}-4x-4. Though the factors -2 and 2 do multiply to make -4, the middle term does not work, because you needed to get {\displaystyle -11x}-11x, not {\displaystyle -4x}-4x.

7 0
3 years ago
PLEASE HELP I WILL GIVE YOU 5 STARS AND A THANKS AND BRAINLIEST (If you tell me how to make you brainliest, lol) What is 81.8181
kirza4 [7]

Answer:

81.82%

Step-by-step explanation:

cuz meth

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