$Given:\\m=3kg\\E=2.7\cdot 10^{17}J\\\\Find:\\c=?\\\\Solution:\\\\E=mc^2\\\\c^2= \frac{E}{m} \\\\c= \sqrt{\frac{E}{m}} \\\\c= \sqrt{ \frac{2.7\cdot 10^{17}J}{3} } = (2.7\cdot 10^{16} \frac{m^2}{s^2} )^{ \frac{1}{2} }=3\cdot 10^{8} \frac{m}{s}$

6 0

3 years ago

Change 20% into a fraction

OlgaM077 [116]

I think it’s just 20/100

5 0

4 years ago

Read 2 more answers

Find three solutions for the equation 2x+y=-4

Svetllana [295]

I would start by plugging in a number for x. Just any random number. Let's take 2 for example. Then the equation would go from 2x + y = -4, to 2(2) + y = -4. Then solve.

2(2) + y = -4
4 + y = -4, after you've done that, plug in a number for y, that completes the equation. In this case, the only acceptable number, would be -8. Because it completes the number sentence.

4 + (-8) = -4
-4 = -4.

Now plug in other numbers, to get the same outcome. Hope this helped!

-Twixx

7 0

4 years ago