Answer:
10 cm
Step-by-step explanation:
From the diagram,
Applying,
lw = 5/2(bh)..................... Equation 1
Where l = length of the rectangle, w = width of the rectangle, b = base of the triangle, h = height of the triangle.
make w the subject of the equation
w = 5(bh)/2l............... Equation 2
From the diagram,
Given: l = 12 cm, b = 6 cm, h = 8 cm
Substitute into equation 2
w = 5(6×8)/(2×12)
w = 10 cm
Hence the width of the rectangle is 10 cm
-6p < 12 Divide -6 on both sides to get "p" by itself

p > -2
When you divide or multiply a negative number to both sides of the inequality, the sign (< , > , ≤ , ≥) is flipped.
Splitting up the interval of integration into
subintervals gives the partition
![\left[0,\dfrac1n\right],\left[\dfrac1n,\dfrac2n\right],\ldots,\left[\dfrac{n-1}n,1\right]](https://tex.z-dn.net/?f=%5Cleft%5B0%2C%5Cdfrac1n%5Cright%5D%2C%5Cleft%5B%5Cdfrac1n%2C%5Cdfrac2n%5Cright%5D%2C%5Cldots%2C%5Cleft%5B%5Cdfrac%7Bn-1%7Dn%2C1%5Cright%5D)
Each subinterval has length
. The right endpoints of each subinterval follow the sequence

with
. Then the left-endpoint Riemann sum that approximates the definite integral is

and taking the limit as
gives the area exactly. We have

Answer:
First, subtract the budgeted amount from the actual expense. If this expense was over budget, then the result will be positive.
Next, divide that number by the original budgeted amount and then multiply the result by 100 to get the percentage over budget. If your expenses were lower than your budgeted amount, then this number will be negative, describing the percentage under budget.
Answer:
perpendicular
Step-by-step explanation:
To determine if AB and CD are parallel, perpendicular, or neither, we need to get the slope of AB and CD first
Given A (−1, 3), B (0, 5),
Slope Mab = 5-3/0-(-1)
Mab = 2/1
Mab = 2
Slope of AB is 2
Given C (2, 1), D (6, −1)
Slope Mcd = -1-1/6-2
Mcd = -2/4
Mcd = -1/2
Slope of CD is -1/2
Take their product
Mab * Mcd = 2 * -1/2
Mab * Mcd = -1
Since the product of their slope is -1, hence AB and CD are perpendicular