Answer:
perimeter is 4 sqrt(29) + 4pi cm
area is 40 + 8pi cm^2
Step-by-step explanation:
We have a semicircle and a triangle
First the semicircle with diameter 8
A = 1/2 pi r^2 for a semicircle
r = d/2 = 8/2 =4
A = 1/2 pi ( 4)^2
=1/2 pi *16
= 8pi
Now the triangle with base 8 and height 10
A = 1/2 bh
=1/2 8*10
= 40
Add the areas together
A = 40 + 8pi cm^2
Now the perimeter
We have 1/2 of the circumference
1/2 C =1/2 pi *d
= 1/2 pi 8
= 4pi
Now we need to find the length of the hypotenuse of the right triangles
using the pythagorean theorem
a^2+b^2 = c^2
The base is 4 ( 1/2 of the diameter) and the height is 10
4^2 + 10 ^2 = c^2
16 + 100 = c^2
116 = c^2
sqrt(116) = c
2 sqrt(29) = c
Each hypotenuse is the same so we have
hypotenuse + hypotenuse + 1/2 circumference
2 sqrt(29) + 2 sqrt(29) + 4 pi
4 sqrt(29) + 4pi cm
The corresponding sides of the model and the actual bridge are in proportion because the two solids are similar.
The scale factor from the model to the actual bridge is 5/25 = 6/30 = 8/40 = 1/5.
Answer: 1/5
Answer:
x+46
Explanation:
4(−8x+5)−(−33x−26)
Distribute the Negative Sign:
=4(−8x+5)+−1(−33x−26)
=4(−8x+5)+−1(−33x)+(−1)(−26)
=4(−8x+5)+33x+26
Distribute:
=(4)(−8x)+(4)(5)+33x+26
=−32x+20+33x+26
Combine Like Terms:
=−32x+20+33x+26
=(−32x+33x)+(20+26)
=x+46
Answer:
you can do a trial and improvement
Step-by-step explanation:
