Answer:
a is your answer to be on the good side i will go with a
Step-by-step explanation:
Aw snap I better answer then lol
<h2>Answer</h2>
2
<h2>Explanation</h2>
First, we are going to use the law of fractional exponents: ![a^{\frac{1}{n} =\sqrt[n]{a}](https://tex.z-dn.net/?f=a%5E%7B%5Cfrac%7B1%7D%7Bn%7D%20%3D%5Csqrt%5Bn%5D%7Ba%7D)
We can infer form our expression that
and
, so let's replace the values:
![a^{\frac{1}{n} =\sqrt[n]{a}](https://tex.z-dn.net/?f=a%5E%7B%5Cfrac%7B1%7D%7Bn%7D%20%3D%5Csqrt%5Bn%5D%7Ba%7D)
![16^{\frac{1}{4} }=\sqrt[4]{16}](https://tex.z-dn.net/?f=16%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D%3D%5Csqrt%5B4%5D%7B16%7D)
Notice that we can also decompose 16 into prime factors to get
, so we can rewrite our expression as follows:
![\sqrt[4]{16}=\sqrt[4]{2^4}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B16%7D%3D%5Csqrt%5B4%5D%7B2%5E4%7D)
Finally, we can use the rule of radicals:
, so:
![\sqrt[4]{2^4}=2](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B2%5E4%7D%3D2)