Answer:
Step-by-step explanation:
To find the first table y = 4x + 2, to find each y value we have to substitute each x value into the equation.
4(-2) + 2 = -6 so -2 is going to have the y as -6
4(-1) + 2 = -2 so -1 is going to have the y as -2
4(0) + 2 = 2 so 0 is going to have the y as 2
4(1) + 2 = 6 so 1 is going to have the y as 6
4(2) + 2 = 10 so 2 is going to have the y as 10
So these are the points you would graph (-2, -6), (-1, -2), (0, 2), (1,6), and (2, 10)
For the next talbe y = 3x + 1 we do the same thing
3(-2) + 1 = -5 so -2 is going to have the y as -5
3(-1) + 1 = -2 so -1 is going to have the y as -2
3(0) + 1 = 1 so 0 is going to have the y as 1
3(1) + 1 = 4 so 1 is going to have the y as 4
3(2) + 1 = 7 so 2 is going to have the y as 7
The ooints to graph are (-2, -5), (-1, -2),(0,1), (1, 4) and (2,7)
For the next table y = 6x - 5
6(-2) - 5 = -17 so -2 is going to have the y as -17
6(-1) - 5 = -11 so -1 is going to have the y as -11
6(0) - 5 = -5 so 0 is going to have the y as -5
6(1) - 5 = 1 so 1 is going to have the y as 1
6(2) - 5 = 7 so 2 is going to have the y as 7
The points to graph (-2, -17), (-1, -11), (0, -5), (1, 1) and (2, 7)
For the next table y = 5 + 2x
5 + 2(-4) = -3 so -4 is going to have the y as -3
5 + 2(-2) = 1 so -2 is going to have the y as 1
5 + 2(0) = 5 so 0 is going to have the y as 5
5 + 2(3) = 11 so 3 is going to have the y as 11
5 + 2(5) = 15 so 5 is going to have the y as 15
(-4, -3), (-2, 1), (0, 5), (3, 11) and (5, 15)
For the next table y = 8x - 10
8(-4) - 10 = -42 so -4 is going to have the y as -42
8(-2) - 10 = -26 so -2 is going to have the y as -26
8(0) - 10 = -10 so 0 is going to have the y as -10
8(2) - 10 = 6 so 2 is going to have the y as 6
8(4) - 10 = 22 so 4 is going to have the y as 22
(-4, -42), (-2, -26), (0, -10), (2, 6) and (4, 22)
For the last table
2(-2) = -4 so -2 is going to have the y as -4
2(-1) = -2 so -1 is going to have the y as -2
2(0) = 0 so 0 is going to have the y as 0
2(-1) = -2 so -1 is going to have the y as -2
2(-2) = -4 so -2 is going to have the y as -4
(-2, -4), (-1, -2), (0, 0), (-1, -2) and (-2, -4)
