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The value of ΔG° at 181.0 °C for the formation of calcium chloride from calcium metal and chlorine gas is ________ kJ/mol. At 25

aleksandr82 [10.1K]

Answer:

$\Delta G^{0}$ at 181.0 $^{0}\textrm{C}$ is -723.3 kJ/mol.

Explanation:

We know, $\Delta G^{0}=\Delta H^{0}-T\Delta S^{0}$

where, T is temperature in kelvin.

Let's assume $\Delta H^{0}$ and $\Delta S^{0}$ does not change in the temperature range 25.0 $^{0}\textrm{C}$ - 181.0 $^{0}\textrm{C}$ .

$181.0^{0}\textrm{C}$ = (273+181.0) K = 454.0 K

Hence, at 181.0 $^{0}\textrm{C}$ , $\Delta G^{0}=(-795.8kJ/mol)-[(454.0 K)\times (-159.8\times 10^{-3}kJ/K.mol)]$

= -723.3 kJ/mol

5 0

3 years ago

Estimate the molecular weight of a polymer if a 100.-mL solution of 6.5 g of the polymer in toluene has an osmotic pressure of 0

MakcuM [25]

Mona le supe te gustan

8 0

3 years ago

if a gas has an initial pressure of 24,650 pa and an initial volume of 376 ml, what is the final volume if the pressure of the g

NNADVOKAT [17]

If a gas has an initial pressure of 24,650 pa and an initial volume of 376 ml, then the final volume would be 11,943.8144 ml if the pressure of the gas is changed to 775 torr assuming that the amount and the temperature of the gas remain constant.

It is given that the initial pressure P₁ is 24,650Pa and initial volumeV₁ is 376ml and the final pressureP₂ is 775 torr. We need to find the final volume of the gas. The final volume could be found using the following formula:

P₁V₁ = P₂V₂

By substituting the values, we get

24650 x 376 = 776 x V₂

9268400 = 776V₂

V₂ = 9268400/776

V₂ = 11,943.8144 ml

Therefore, the final volume of the gas would be 11,943.8144 ml

To know more about Partial pressure, click below:

brainly.com/question/14119417

#SPJ4

5 0

11 months ago

A ball is rolled at a velocity of 3 m/s and rolls for 5 seconds. How far does the ball roll? *

MrRa [10]

Answer 15m

Explanation: Distance = Speed x Time

3 x 5 =15

6 0

2 years ago

A buffer solution contains 0.345 M acetic acid and 0.377 M sodium acetate . If 0.0613 moles of potassium hydroxide are added to

melamori03 [73]

Answer:

pH = 5.54

Explanation:

The pH of a buffer solution is given by the Henderson-Hasselbach (H-H) equation:

pH = pKa + log $\frac{[CH_3COO^-]}{[CH_3COOH]}$

For acetic acid, pKa = 4.75.

We calculate the original number of moles for acetic acid and acetate, using the given concentrations and volume:

CH₃COO⁻ ⇒ 0.377 M * 0.250 L = 0.0942 mol CH₃COO⁻

CH₃COOH ⇒ 0.345 M * 0.250 L = 0.0862 mol CH₃COOH

The number of CH₃COO⁻ moles will increase with the added moles of KOH while the number of CH₃COOH moles will decrease by the same amount.

Now we use the H-H equation to calculate the new pH, by using the new concentrations:

pH = 4.75 + log $\frac{(0.0942+0.0613)mol/0.250L}{(0.0862-0.0613)mol/0.250L}$ = 5.54

6 0

3 years ago