The specific heat of the unknown metal is 0.859 J/g⁰C.
<h3>Specific heat of the unknown metal</h3>
Heat lost by the unknown metal = Heat gained by water
m₁c₁Δθ₁ = m₂c₂Δθ₂
where;
- c₁ is specific heat of the unknown metal
- c₂ is specific heat of water
(15)(c₁)(99 - 26) = (75)(4.18)(26 - 23)
1095c₁ = 940.5
c₁ = 940.5/1095
c₁ = 0.859 J/g⁰C
Learn more about specific heat here: brainly.com/question/16559442
#SPJ1
The question requires that you assume complete ionization of the compound. This is:
(NH4)2 SO4 → 2 NH4 (+) + SO4 (2-)
Then, 1 mol of (NH4)2 SO4 produces 3 moles of ions: 2 moles of NH4 (+) and 1 mol of SO4 (2-)
=> 0.26 * 2 moles of NH4(+) = 0.52 moles of NH4 (+)
0.26 * 1 mol of SO4 (2-) = 0.26 moles of SO4 (2-).
Answer: 0.52 moles of ammonium ions and 0.26 moles of sulfate.ions.
Answer:
Rate = 1.321M/s[H₂CO₃]¹ ; k = 1.32M/s
Explanation:
Solution..
---------------
Let's calculate the mass of CO₂.
We have (12+(16*2))
= 12+32
=44gmol¯¹..
a. What is the percent by mass of carbon?
Mass of carbon /mass of CO₂ × 100%
12/44 × 100%
=27.3%...
b. What is the percent by mass of oxygen?
Mass of oxygen/mass of CO₂ × 100%
(2×16)/44 × 100%
32/44 × 100%
=72.7%....
To check.. You'll add this two percentage compositions together and see of it gives 100%... If it does then we're good...
27.3%+72.7% = 100%.... Checked..
Hope this helped....?
Higher humidity because there's more H2O in the air
