Where's the list? If you show it maybe I can help
I believe it’s c because if you really read and close read it will make more sense
Answer:
8.3 × 10³ mL
Explanation:
Step 1: Calculate the mass of water that contains 100 mg of Pb
The concentration of Pb in the sample is 0.0012% by mass, that is, there are 0.0012 g of Pb every 100 g of water. The mass of water that contains 100 mg (0.100 g) of Pb is:
0.100 g Pb × 100 g Water/0.0012 g Pb = 8.3 × 10³ g Water
Step 2: Calculate the volume corresponding to 8.3 × 10³ g of water
Since the solution is diluted, we will assume the density of the sample is equal than the density of water (1 g/mL).
8.3 × 10³ g × 1 mL/1 g = 8.3 × 10³ mL
Answer is: 1 × 10⁻¹⁰ meter or 0.0000000001 meter.
The atomic radius is a measure of the size of the atom.
It is distance from the center of the nucleus of atom to the boundary of electron cloud.
The radius of atoms is between 30 and 300 pm (10⁻¹² m) or between 0.3 and 3 angstroms (10⁻¹⁰ m).
The radius generally decrease along each period of the Periodic table.
V( H₂SO₄) = 25.0 mL in liters = 25.0 / 1000 = 0.025 L
M(H₂SO₄) = ?
V(NaOH) = 50.0 mL = 50.0 / 1000 = 0.05 L
M(NaOH) = 0.150 M
number of moles NaOH :
n = M x V
n = 0.150 x <span> 0.05
</span>
n = 0.0075 moles of NaOH
H₂SO₄(aq) + 2 NaOH(aq) = Na₂SO₄(aq) + 2 H₂O(l)
1 mole H₂SO₄ ---------- 2 mole NaOH
? mole H₂SO₄ ---------- 0.0075 moles NaOH
moles = 0.0075 * 1 / 2
= 0.00375 moles of H₂SO₄
M(H₂SO₄) = n / V
M = 0.00375 / <span> 0.025
</span>= 0<span>.15 M
</span>
hope this helps!
