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garri49 [273]
3 years ago
6

A- is a weak base. which equilibrium corresponds to the equilibrium constant ka for ha?

Chemistry
1 answer:
vekshin13 years ago
5 0

Answer:

K_a=\frac{[H^+][A^-]}{[HA]}

Explanation:

ka is defined as the dissociation constant of an acid. It is defined as the ratio of concentration of products to the concentration of reactants.

For the dissociation of weak acid, the chemical equation follows:

HA\rightleftharpoons H^++A^-

The equilibrium constant is defined by the equilibrium concentration of products over reactants:

K_a=\frac{[H^+][A^-]}{[HA]}

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Lead is a toxic metal that affects the central nervous system. A Pb-contaminated water sample contains 0.0012 % Pb by mass. What
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Answer:

8.3 × 10³ mL

Explanation:

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3 0
2 years ago
What is a reasonable estimate for the radius of an atom?
Romashka [77]

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7 0
3 years ago
A 25.0-mL sample of an H2SO4 solution requires 50.0 mL of 0.150 M NaOH to completely react with the H2SO4. What was the concentr
Nitella [24]
V( H₂SO₄) = 25.0 mL in liters = 25.0 / 1000 = 0.025 L
 M(H₂SO₄) = ?

V(NaOH) = 50.0 mL = 50.0 / 1000 = 0.05 L 
M(NaOH) = 0.150 M

number of moles NaOH :

n = M x V

n = 0.150 x <span> 0.05 
</span>
n = 0.0075 moles of NaOH 

H₂SO₄(aq) + 2 NaOH(aq) = Na₂SO₄(aq) + 2 H₂O(l)

1 mole H₂SO₄ ---------- 2 mole NaOH
? mole H₂SO₄ ---------- 0.0075 moles NaOH

moles = 0.0075 * 1 / 2

= 0.00375 moles of H₂SO₄

M(H₂SO₄) = n / V

M = 0.00375 / <span> 0.025

</span>= 0<span>.15 M
</span>
hope this helps!

8 0
3 years ago
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