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Elina [12.6K]
3 years ago
7

PLEASE HELP ME WITH THIS HOME WORK

Mathematics
1 answer:
dem82 [27]3 years ago
4 0

I totally understand that was exactly how my life was what are the homework problems?

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If its $2.10 for 500ml how much is it for 100 ml per unit
bija089 [108]
To answer this question, all you have to do is divide 2.10 by 5.

2.10 ÷ 5 = 0.42

It is $0.42 for 100 mL
3 0
3 years ago
The radius of a cylindrical vessel is 7 cm and height is 1400 m . Find the cost of painting its inner curved surface area at the
Olegator [25]

Answer:

Cost = 616000 DHS per square centimetre.

Step-by-step explanation:

curved surface of a cylinder = 2\pirh

r = 7 cm

h = 1400 m = 140000 cm

The outer curved surface area of the cylinder = inner curved surface area of the cylinder

The inner curved surface of the cylinder = 2\pirh

                                      = 2 x \frac{22}{7} x 7 x 140000

                                      = 2 x 22 x 1 x 140000

                                      = 6160000

The inner curved surface of the cylinder is 6160000 square centimetre.

But, the cost of painting is at the rate of 10 DHS per square centimetre.

The inner curved surface of the cylinder = 6.16 x 10^{6} square centimetre.

cost of painting the inner curved surface area = \frac{6.16*10^{6} }{10}

                                                                       = 616000 DHS per square centimetre

The cost of painting the inner surface is 616000 DHS per square centimetre.

6 0
3 years ago
For each pair of similar figures, find the ratio of the area of the first figure to the area of the second.
Hitman42 [59]

answer:

\frac{4}{9}


explanation:

the area of the larger square is 36 (6*6), and the area of the smaller square is 16 (4*4). to find the ratio of the area, simply just put 16 over 36 and simplify.

\frac{16}{36} = \frac{4}{9}

--

if this helped, please consider giving brainliest !

7 0
3 years ago
I have no clue what I'm doing
sergejj [24]
Try to get all the x'es to the right side
5 0
3 years ago
Let f ( ) sin(arctan ) x x = . What is the range of f ?
nikklg [1K]
<span>So you have composed two functions,
</span><span>h(x)=sin(x) and g(x)=arctan(x)</span>
<span>→f=h∘g</span><span>
meaning
</span><span>f(x)=h(g(x))</span>
<span>g:R→<span>[<span>−1;1</span>]</span></span>
<span>h:R→[−<span>π2</span>;<span>π2</span>]</span><span>
And since
</span><span>[−1;1]∈R→f is defined ∀x∈R</span><span>

And since arctan(x) is strictly increasing and continuous in [-1;1] ,
</span><span>h(g(]−∞;∞[))=h([−1;1])=[arctan(−1);arctan(1)]</span><span>
Meaning
</span><span>f:R→[arctan(−1);arctan(1)]=[−<span>π4</span>;<span>π4</span>]</span><span>
so there's your domain</span>
5 0
3 years ago
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