-4x + 6y = 12
x + 2y = -10
First solve for x in the second equation
x + 2y = -10
x = -10 - 2y
Now we have a value for x so we can substitute it into the other equation
-4 (-10 - 2y) + 6y = 12
Now solve for y
40 + 8y + 6y = 12
40 + 14y = 12
14y = -28
y = -2
Now we have a value for y that we can plug into one of the original equations so we can solve for x
x + 2y = -10
x + 2(-2) = -10
x - 4 = -10
x = -6
Your solution set is
(-6, -2)
You're probably supposed to find the value of p and not x, which is impossible to do.
Expanding gives
We're told that
which we can use to solve for p:
Answer:
(0,0)
Step-by-step explanation:
x^2+y^2=4^2
center: (0,0)
radius=4
Answer:
can u give more information than i will answer
Step-by-step explanation:
Answer:
180
Step-by-step explanation:
