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Nat2105 [25]
3 years ago
6

What is the equation of the line that goes through (2, 2) and is perpendicular to y = 5x + 3?

Mathematics
1 answer:
Marina CMI [18]3 years ago
5 0
Y = 5x + 3.....the slope here is 5. A perpendicular line will have a negative reciprocal slope. To find the negative reciprocal, we flip the original slope and change the sign. So we have slope 5 or 5/1.....flip it and it becomes 1/5....change the sign and it becomes - 1/5. So our perpendicular line will have a slope of -1/5.

y = mx + b
slope(m) = -1/5
(2,2)....x = 2 and y = 2
now we sub into the formula and find b, the y int
2 = -1/5(2) + b
2 = -2/5 + b
2 + 2/5 = b
10/5 + 2/5 = b
12/5 = b
so ur perpendicular equation is : y = -1/5x + 12/5 <==
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4 0
3 years ago
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MAXImum [283]

Answer:

<h2>7</h2>

Step-by-step explanation:

\left[\left(11\:-\:4\right)^3\right]^2\:\div \left(4\:+\:3\right)^5\\\\\frac{\left(\left(11-4\right)^3\right)^2}{\left(4+3\right)^5}\\\\\mathrm{Subtract\:the\:numbers:}\:11-4=7\\\\=\frac{\left(7^3\right)^2}{\left(4+3\right)^5}\\\\\mathrm{Add\:the\:numbers:}\:4+3=7\\\\=\frac{\left(7^3\right)^2}{7^5}\\\\\left(7^3\right)^2=7^6\\\\=\frac{7^6}{7^5}\\\\\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=x^{a-b}\\\\\frac{7^6}{7^5}=7^{6-5}\\\\\mathrm{Subtract\:the\:numbers:}\:6-5=1\\\\=7

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3 years ago
PLZ HURRY IT'S URGENT!!!!!!
Anton [14]

I think the correct answer your looking for is D) 9

5 0
3 years ago
Read 2 more answers
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