Answer:
Step-by-step explanation:
d
For the writing assignment, the number of ways of choosing from two essay topics three different mandatory lengths is given by:
![^2C_1 \times { ^3C_1}= 2\times3=6](https://tex.z-dn.net/?f=%20%5E2C_1%20%5Ctimes%20%7B%20%5E3C_1%7D%3D%202%5Ctimes3%3D6)
Thus, he has 20 choices to make for the writing assignment.
For the reading assignment, the number of ways of choosing from <span>five biographies and three volumes of essays</span> is given by:
5 x 3 = 15
Therefore, the total number of choices is given by 6 + 15 = 21 choices.
Answer:
<u>(1-sinA) * Sin²A</u>
(1+cosA) * Cos²A
<u>(1-sinA) * (1-Cos²A)</u>
(1+cosA) * (1-Sin²A)
<u>(1-sinA) * (1-CosA)(1+CosA)</u>
(1+cosA) * (1-SinA) (1+SinA)
<u>(1-CosA)</u>
(1+SinA)
proved
Answer:
The greatest common divisor (gcd) of two or more numbers referst to the largest positive integer that divides each of the integers. Also, two integers are said to be relatively prime, mutually prime, or coprime if the only positive integer that divides both of them is 1. Therefore, If the GCD of 5 and 12 is one, it means that the two numbers are mutually prime.
The answers would be -3, -2, -1, 0