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MrMuchimi
3 years ago
11

Plz help plz help me​

Mathematics
2 answers:
dmitriy555 [2]3 years ago
7 0
I believe it is D but no promises
storchak [24]3 years ago
3 0
Im pretty sure its d
You might be interested in
For all real numbers a and b, 2a • b = a2 + b2 Is this true or false? Explain why it false or true.
Andru [333]

Answer:

It's false.... correct is a2+2ab+b2

Step-by-step explanation:

This cannot be factored anymore although. when we try to substitute a with 5 and b with 2, the answer in the right hand side of the equation is -9.

That's why it's false.

3 0
3 years ago
Is (1, 2) a solution to the inequality 6x - y> 3?
Lostsunrise [7]

Answer:

<u><em>Yes.</em></u>

Step-by-step explanation:

<em>To find the answer we will put it into the equation, since</em><em><u> x = 1 and y = 2</u></em><em> we will write it like this, </em><u><em>6(1) - 2 > 3.</em></u><em>  Since </em><u><em>6 x 1 = 6</em></u><em>, we will now </em><u><em>subtract 6 from 2 which equals 4</em></u><em>.  Therefore, the equation is </em><u><em>correct because 4 is bigger than 3.</em></u>

5 0
3 years ago
A polynomial has been factored, as shown below: f(x) = (x − 6)(x + 5)(x − 9) What are the zeros of the polynomial? (5 points)
soldi70 [24.7K]

<span>x=6</span>, <span>x=−5</span> or <span>x=9</span>

Explanation:

<span><span>f<span>(x)</span></span>=<span>(x−6)</span><span>(x+5)</span><span>(x−9)</span></span>

If all of the linear factors are non-zero, then so is their product <span>f<span>(x)</span></span>.

If any of the linear factors is zero, then so is their product <span>f<span>(x)</span></span>.

5 0
3 years ago
What is the mass of a copper (II) chloride sample if it contains 0.0344 moles of the compound?
ale4655 [162]

According to the valence number of copper(2+) and the same value for chlorine (1-) copper (II) chloride has the formula of CuCl2

The molar mass of copper is 0,0635 kg/mole and chlorine gas a molar mass of 0,035 kg/mole the compound will have a molar mass of ( 0,0635+2×0,035 )kg/mole=0,099kg/mole and 0,344 moles are equivalent in mass to 0,344×0,135 kg=0,046 kg

5 0
2 years ago
In 2010, the population of Kingsford was 8000. By 2014 the population had increased by 15% and 2/5 of the population was age 12
Anastasy [175]
<h2>Hello!</h2>

The answer is: The population age 12 or under was 3680.

<h2>Why?</h2>

If in 2010 the population of Kignsford was 8000, and by 2014 the population had increased by 15% we need to calculate the total population and then, calculate how many people was age 12 or under.

We must remember that we cannot work with percentage values, so, to make 15% a real number, we need to divide it by 100:

15(Percentage)=\frac{15}{100}=0.15

So,

Calculating the population by 2014, we have:

Population_{2014}=Population_{2010}+ Population_{2010}*0.15

Then, substituting we have:

Population_{2014}=8000+ 8000*0.15=9200

Now, calculating the population that was age 12 or under, knowing that it was 2/5 of the total population, we have:

Population=TotalPopulation*\frac{2}{5}\\\\Population=9200*\frac{2}{5}=3680

So, the population age 12 or under was 3680.

Have a nice day!

6 0
4 years ago
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