27)
Equation of the existing water pipe's line
a) slope, m = rise / run = Δy / Δx = 3/2
b) y-intercept, b = 3
equation: y = mx + b = (3/2)x + 3
Equation of the new water pipe's line
slope, m = - 1 / (slope of the perpendicular line) = - 1 / (3/2) = - 2/3
point (0,2)
=> y - 2 = (-2/3) (x - 0) => y = (-2/3)x + 2 <---- equation of the new pipe
28)
two parallel lines have the same slope =>
slope, m = rise / run = Δy / Δx = [4 - 0] / [11 - 8] = 4 / 3
point (4,5) => y - 5 = (4/3) (x - 4)
=> y = (4/3)x - 16/3 + 5 = (4/3)x - 1/3
y = (4/3)x - 1/3 <--- equation of the new bike path
Answer:
23.27 - 5. 3 = 17.97
Step-by-step explanation:
<span>LJK = KJM
-10x +3 = -x + 21
-10x + x = 21 - 3
-9x = 18
x = -2
KJM = -x + 21 = 2 + 21 = 23
LJM = LJK + KJM
LJM = 23 + 23
LJM = 46º..
i think thats how its done </span>
If angle BCD measures 70° then so does angle DBC (because you have formed an isoceles triangle inside the larger ΔABC and the two legs are equal so the two angles have to be equal. So we have a two 70° angles which leaves 40° for the 3rd angle, which is ∠BDC.
Since ∠BDC and ∠ADB are supplementary (180°) - that leaves 140° for ∠ADB and is our answer
Using the rule (x+5, y+2) you would add 5 to the x value and 2 to the y value so the answer would be L' (7,5) M' (6,4) N' (9,6)
