Explanation:
1 ) first u have to balance the equation but in this case it is already balanced.
2) checking for the limiting reactant:
13 mol O2 × (1mol H2O / 1mol of O2) = 13 mol of H2O
14 mol of ethanol × (1mol H2O/ 1molof ethanol) = 14 mol of H2O
the less amount of moles produced from the O2 so the limiting reactant is oxygen
3) calculating the products moles
13 mol O2 × (1mol H2O / 1mol of O2) = 13 mol
13 mol O2 × (1mol Ch3Cooh / 1mol O2) = 13 mol
note: the ratios obtained from the balanced equation
4) the excess reagent is the ethanol 1 mol will be remain
Answer: Mass is both a property of a physical body and a measure of its resistance to acceleration (rate of change of velocity with respect to time) when a net force is applied. An object's mass also determines the strength of its gravitational attraction to other bodies.
Explanation: This what I could come up with. Hope this helps !!
Given:
K = 0.71 = Kp
The reaction of sulphur with oxygen is
S(s) + O2(g) ---> SO2(g)
initial Pressure 6.90 0
Change -x +x
Equilibrium 6.90-x x
Kp = pSO2 / pO2 = 0.71 = x / (6.90-x)
4.899 - 0.71x = x
4.899 = 1.71x
x = 2.86 atm = pressure of SO2 formed
temperature = 950 C = 950 + 273.15 K = 1223.15 K
Volume = 50 L
Let us calculate moles of SO2 formed using ideal gas equation as
PV = nRT
R = gas constant = 0.0821 L atm / mol K
putting other values
n = PV / RT = 2.86 X 50 / 1223.15 X 0.0821 = 1.42 moles
Moles of Sulphur required = 1.42 moles
Mass of sulphur required or consumed = moles X atomic mass of sulphur
mass of S = 1.42 X 32 = 45.57 grams or 0.04557 Kg of sulphur
the salt is the solute (and the water is the solvent) i hope this answers your question lol
