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Amanda [17]
3 years ago
10

As: [Ar]4s23d104p3 [Ar]4s23d104p2 [Kr]4s24d104p3 [Kr]4s23d104p3

Chemistry
2 answers:
Elan Coil [88]3 years ago
8 0

Answer:

[Ar]4s23d104p3

Explanation:

ollegr [7]3 years ago
5 0

Answer:

[Ar]4s23d104p3 (Option A)

Explanation:

on edge2021 :D

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Damm [24]
I believe it has something to do with the H2O molecules, because a chemical compound is not a mixture.

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Which pair of elements has atoms with the same number of valence electrons ?
RoseWind [281]

Answer:silicon (Si) and geranium (Ge)

Explanation:

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3 years ago
During a titration, the pH of an analyte solution containing HA(aq) is 3.92 and the ratio of [A–]/[HA] is 0.41. What is the Ka o
Solnce55 [7]

Answer:

Ka=4.71x10^{-4}

Explanation:

Hello there!

In this case, according to the Henderson-Hasselbach equation, it is possible to write:

pH=pKa+log(\frac{[A^-]}{[HA]} )

Next, since we are given the pH and the [A–]/[HA] ratio, we can solve for the pKa as shown below:

pKa=pH-log(\frac{[A^-]}{[HA]} )

Now, we plug in the values to obtain:

pKa=3.92-log(0.41 )\\\\pKa=3.33

Next, Ka is:

Ka=10^{-pKa}=10^{-3.33}\\\\Ka=4.71x10^{-4}

Best regards!

3 0
3 years ago
What are the molality and mole fraction of solute in a 22.3 percent by mass aqueous solution of formic acid (HCOOH)?
Vanyuwa [196]

Answer:

Mole fraction for solute = 0.1, or 10%

Molality = 6.24 mol/kg

Explanation:

22.3% by mass → In 100 g of solution, we have  22.3 g of HCOOH

Mass of solution = 100 g

Mass of solute = 22.3 g

Mass of solvent = 100 g - 22.3g = 77.7 g

Let's convert the mass to moles

22.3 g . 1mol/ 46 g = 0.485 moles

77.7 g. 1mol / 18 g = 4.32 moles

Total moles = 4.32 moles + 0.485 moles = 4.805 moles

Xm for solute = 0.485 / 4.805 = 0.100 → 10%

Molality → mol/ kg → we convert the mass of solvent to kg

77.7 g.  1 kg / 1000g = 0.0777 kg

0.485 mol / 0.0777 kg = 6.24 m

6 0
3 years ago
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frutty [35]

Answer:

c

Explanation:

i took the test

4 0
4 years ago
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