P+1/5−1/2=1/10
p+ 10÷5= 2×1=2 =1/10
10÷2= 5*(-1)= -5=1/10
2-5/10
p-3/10 = 1/10
p= 1/10+3/10
p= 4/10
4÷2= 2
10÷2 = 5
>The answer is:
>> P= 2/5
Answer:
3 Numbers: 15, 21, 35
Step-by-step explanation:
We want number that divide 109 with a remainder of 4.
Thus, it can divide of 109 - 4 = 105
Factors of 105 = 3, 5, 7
Thus for getting two digit number it must be Multiple of any two factors of 105.
i.e. 15, 21 and 35
Hence there are only 3 numbers that divide 109 with a remainder of 4.
Answer:
Step-by-step explanation:
um
Solve by elimination.
The goal is to cancel out one of the variables in order to easily solve for the other variable.
Do this by changing the equations so that the coefficients of either x or y add up to 0.
Notice the coefficients of y are 3 and 3, if we make one of them negative then they add up to 0. 3+ (-3) = 0
Multiply 2nd equation by -1.
6x +3y = 9
-2x -3y = -1
__________
4x +0y = 8
Solve for x
4x = 8
x = 8/4 = 2
Plug x=2 back into one of original equations to find y.
---> 2(2) + 3y = 1
---> 4 + 3y = 1
---> 3y = -3
---> y = -1
Therefore solution is (2,-1)
Answer:15
Step-by-step explanation:1) 1/2
2) 3/5
3)4
D) 8
5) 16
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