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zvonat [6]
3 years ago
7

Find derivative of 2cosx+2cos2x

Mathematics
1 answer:
Zarrin [17]3 years ago
7 0
Derivitive of cosx=-sinx
dy/dx sinx=cosx
and use chain rue

2cosx=-2sinx
2cos2x=-4sin2x
so
-2sinx-4sin2x id the deritivitve
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2 years ago
3^2 - 2x + 4 and g(x) = 5x^2 + 6x - 8 find f-g(x)
sveta [45]

Answer:

For the given functions f(x) and g(x) (f-g)(x) = -2x^{2}  - 8x +12

Step-by-step explanation:

Here, the given function are:

f(x)  = 3x^{2}  - 2x+ 4\\g(x) = 5x^{2}  + 6x -8

Now, simplifying for (f-g)(x)  =  f(x) -  g(x):

f(x) - g(x)  = (3x^{2}  - 2x+ 4) - (5x^{2}  + 6x -8)

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Doing operation on LIKE TERMS,  we get

f(x) -  g(x) = ( 3x^{2}- 5x^{2})   + (-2x - 6x)  +( 4 +8) = -2x^{2}  - 8x + 12

Hence, for the given functions f(x) and g(x) (f-g)(x) = -2x^{2}  - 8x +12

4 0
3 years ago
Find the value for x? X-5+5x-12=25
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