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MAXImum [283]
3 years ago
9

Solve this problems using the equation: C = λ x ν........ A microwave oven emits radiation at a wavelength of 5.00 x 10e-5 m. Wh

at is the frequency of this radiation?
Chemistry
1 answer:
stira [4]3 years ago
4 0

Answer:

c = λ x ν

v =c/λ=(3*10e8)/(5.00 x 10e-5)=6000000000000

f = v/λ =6000000000000/5.00 x 10e-5=120000000

Explanation:

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An electron moved from a higher energy level to a lower energy level. What most likely happened during the transition? (4 points
Alex787 [66]

Answer: The anwser is A a photon was realeased please mark brainliest

Explanation:

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3 years ago
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2 years ago
Suppose that the microwave radiation has a wavelength of 12.4 cm . How many photons are required to heat 255 mL of coffee from 2
vivado [14]

Answer:

Explanation:

wavelength λ = 12.4 x 10⁻² m .

energy of one photon = h c / λ

= 6.6 x 10⁻³⁴ x 3 x 10⁸ /  12.4 x 10⁻²

= 1.6 x 10⁻²⁴ J .

Let density of coffee be equal to density of water .

mass of coffee = 255 x 1 = 255 g

heat required to heat up coffee = mass x specific heat x rise in temp

= 255 x 4.18 x ( 62-25 )

= 39438.3 J  .

No of photons required = heat energy required / energy of one photon

= 39438.3 / 1.6 x 10⁻²⁴

= 24649 x 10²⁴

= 24.65 x 10²⁷ .

5 0
3 years ago
Which statement is true about limiting reactants?
Paraphin [41]

Answer:

The limiting reactant in a reaction is the first reactant to be completely converted to products.

Explanation:

When we perform a reaction, it is not easy to measure the exact amount of the two reagents to make sure that both of them react completely. That's why typically we have a limiting reagent and a reagent in excess.

The limiting reagent is the one which determines the maximum amount of product formed, as when it's used up, the reaction stops and cannot proceed further, since the other reagent doesn't have anything to react with.

Simply speaking, the limiting reactant in a reaction is the first reactant to be completely converted to products.

The limiting reagent provides the information about the amount of the product formed, as opposed to the reagent in excess which doesn't provide any valuable information.

7 0
3 years ago
Exprese la concentración de una solución de H3PO4 al 30 % en masa y con una densidad de 1.39 g/mL en: M, y N.
Advocard [28]

Respuesta:

4.26 M; 12.8 N

Explicación:

Primer paso: Calcular la concentración volumétrica (Cv)

Usaremos la siguiente expression.

Cv = Cg × ρ

Cv = 30 g%g × 1.39 g/mL = 41.7 g%mL

Segundo paso: Calcular la molaridad

La concentración volumetrica es 41.7 g%mL, es decir, hay 41.7 gramos de soluto cada 100 mL de solución. Usaremos la siguiente fórmula para molaridad.

M = masa de soluto / masa molar de soluto × litros de solución

M = 41.7 g / 97.99 g/mol × 0.1 L = 4.26 M

Tercer paso: Calcular la normalidad

Usaremos la siguiente fórmula.

N = M × Z

donde Z para un ácido es igual al número de protones.

N = M × Z

N = 4.26 mol/L × 3 eq/mol = 12.8 N

3 0
3 years ago
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