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yuradex [85]
2 years ago
13

The recommended maintenance dose of penicillin for children is 1.0 mg/kg/hr by injection. Of 10 mL of a 25 mg/mL solution of pen

icillin is added to a 100 mL bottle of saline, what is the delivery rate for a 40 pound child
Chemistry
1 answer:
SOVA2 [1]2 years ago
5 0

This problem is providing us with the recommended maintenance dose of penicillin for children as 1.0 mg/kg/hr by injection. Thus, the delivery rate for a 40-pound child is required, if 10 mL of a 25 mg/mL solution of penicillin is added to a 100-mL bottle of saline. At the end, the result is 8.0 mL/hr:

<h3>Dimensional analysis:</h3>

In chemistry, dimensional analysis allows us to obtain a specific result given relevant information about it. Although a formula is not always provided, one can use the units as a reference for the calculations.

For example, this problem asks for the rate, in mL/hr, at which a child gets this dose, so the first step will be to get the mass of the child in kilograms:

40 lb*\frac{0.4536kg}{1lb}= 18.144kg

Next, we calculate the rate at which the penicillin is delivered to this child:

1.0\frac{mg}{kg*hr} *18.144kg=18.144\frac{mg}{hr}

After that, we calculate the total mass of penicillin that is delivered:

10mL*25\frac{mg}{mL} =250 mg

And get the new concentration once it is diluted to 100 mL:

\frac{250mg}{10mL+100mL}=2.27\frac{mg}{mL}

And finally, we combine the mg/hr with the mg/mL to get the result in mL/hr as required:

18.144\frac{mg}{hr} *\frac{1mL}{2.27mg}\\ \\=8.0\frac{mL}{hr}

Learn more about dimensional analysis: brainly.com/question/10874167

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For the following electron-transfer reaction:
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Answer:

1. The oxidation half-reaction is: Mn(s) ⇄ Mn²⁺(aq) + 2e⁻

2. The reduction half-reaction is: Ag⁺(aq) + 1e⁻ ⇄ Ag(s)  

Explanation:

Main reaction: 2Ag⁺(aq) + Mn(s) ⇄ 2Ag(s) + Mn²⁺(aq)

In the oxidation half reaction, the oxidation number increases:

Mn changes from 0, in the ground state to Mn²⁺.

The reduction half reaction occurs where the element decrease the oxidation number, because it is gaining electrons.

Silver changes from Ag⁺ to Ag.

1. The oxidation half-reaction is: Mn(s) ⇄ Mn²⁺(aq) + 2e⁻

2. The reduction half-reaction is: Ag⁺(aq) + 1e⁻ ⇄ Ag(s)  

To balance the hole reaction, we need to multiply by 2, the second half reaction:

Mn(s) ⇄ Mn²⁺(aq) + 2e⁻

(Ag⁺(aq) + 1e⁻ ⇄ Ag(s)) . 2

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4 0
4 years ago
PLEASE HELP
neonofarm [45]

Answer:

The answer to your question is 0.10 M

Explanation:

Data

Molarity = ?

mass of Sucrose = 125 g

volume = 3.5 l

Formula

Molarity = moles / volume

Process

1.- Calculate the molar mass of sucrose

C₁₂H₂₂O₁₁ = (12 x 12) + (1 x 22) + (16 x 11)

               = 144 + 22 + 176

               = 342 g

2.- Convert the mass of sucrose to moles

                  342 g of sucrose ------------------- 1 mol

                  125 g of sucrose -------------------- x

                           x = (125 x 1) / 342

                           x = 0.365 moles

3.- Calculate the molarity

Molarity = 0.365 / 3.5

4.- Result

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5 0
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Answer:

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From the question we are told that

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Here \Delta  H is the change in enthalpy

\Delta  U is the change in the internal energy

              \Delta N  is the difference between that number of moles of product and the number of moles of reactant

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So  

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The  negative sign in the equation tell us that the enthalpy\Delta_r H would be less than the Internal energy \Delta_r U

4 0
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