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yuradex [85]
2 years ago
13

The recommended maintenance dose of penicillin for children is 1.0 mg/kg/hr by injection. Of 10 mL of a 25 mg/mL solution of pen

icillin is added to a 100 mL bottle of saline, what is the delivery rate for a 40 pound child
Chemistry
1 answer:
SOVA2 [1]2 years ago
5 0

This problem is providing us with the recommended maintenance dose of penicillin for children as 1.0 mg/kg/hr by injection. Thus, the delivery rate for a 40-pound child is required, if 10 mL of a 25 mg/mL solution of penicillin is added to a 100-mL bottle of saline. At the end, the result is 8.0 mL/hr:

<h3>Dimensional analysis:</h3>

In chemistry, dimensional analysis allows us to obtain a specific result given relevant information about it. Although a formula is not always provided, one can use the units as a reference for the calculations.

For example, this problem asks for the rate, in mL/hr, at which a child gets this dose, so the first step will be to get the mass of the child in kilograms:

40 lb*\frac{0.4536kg}{1lb}= 18.144kg

Next, we calculate the rate at which the penicillin is delivered to this child:

1.0\frac{mg}{kg*hr} *18.144kg=18.144\frac{mg}{hr}

After that, we calculate the total mass of penicillin that is delivered:

10mL*25\frac{mg}{mL} =250 mg

And get the new concentration once it is diluted to 100 mL:

\frac{250mg}{10mL+100mL}=2.27\frac{mg}{mL}

And finally, we combine the mg/hr with the mg/mL to get the result in mL/hr as required:

18.144\frac{mg}{hr} *\frac{1mL}{2.27mg}\\ \\=8.0\frac{mL}{hr}

Learn more about dimensional analysis: brainly.com/question/10874167

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Given the chemical equation: 2 Pb + O2 → 2 PbO, if 51.8 grams of Pb are formed in this reaction, then 8.00 grams of O2 must have
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Answer:

If 51.8 of Pb is reacting, it will require 4.00 g of O2

If 51.8 g of PbO is formed, it will require 3.47 g of O2.

Explanation:

Equation of the reaction:

2 Pb + O2 → 2 PbO

From the equation of reaction, 2 moles of lead metal, Pb, reacts with 1 mole of oxygen gas, O2, to produce 2 moles of lead (ii) oxide, PbO

Molar mass of Pb = 207 g

Molar mass of O2 = 32 g

Molar mass of PbO = 207 + 32 = 239 g

Therefore 2 × 207 g of Pb reacts with 32 g of O2 to produce 2 × 239 g of PbO

= 414 g of Pb reacts with 32 g of O2 to produce 478 g of PbO

Therefore, formation of 51.8 g of PbO will require (32/478) × 51.8 of O2 = 3.47 g of O2.

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What is the specific heat of a substance if 6527 J are required to raise the temperature of a 312 g sample by 15 degrees Celsius
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Answer:

1.395J/g°C

Explanation:

The following were obtained from the question:

Q = 6527J

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C =?

Q = MCΔT

C = Q/MΔT

C = 6527/(312 x 15)

C = 1.395J/g°C

The specific heat capacity of the substance is 1.395J/g°C

3 0
3 years ago
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