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scZoUnD [109]
1 year ago
15

1-104. Solve each equation. Give solutions in both exact and approximate forms. HomeworkHelpa. X2+3x-3=0b. 3x2-7x=12

Mathematics
1 answer:
Alex_Xolod [135]1 year ago
8 0

According to the given question we have the following equations:

a. x2+3x-3=0

b. 3x2-7x=12

a. X2+3x-3=0

The first step to calculate this equation is:

Move the -3 to the other side:

So, the equation would be:

X2+3x=3

x2+3x=5x

Therefore:

5x=3

x=3/5

a. The value of x would be 3/5

b. 3x2-7x=12

First step:

Multyply 3x to 2, so:

3x*2=6x

Next we can proceed to calculate the value of x:

6x-7x=12

-x=12

x=-12

b. The value of x would be -12

1

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the nth term of a sequence is given by an²+bn where a and b are integers the 2nd term of the sequence is 2 4th term of the seque
stealth61 [152]

Answer:

54

Step-by-step explanation:

Tn = an²+bn

T2 = a2²+2b

2 = 4a +2b

Multiply all through by 2

4 = 8a +4b

4b = 4-8a

T4 = a4² + 4b

20 = 16a +4b

4b = 20-16a

4-8a = 20-16a

16a -8a = 20-4

8a = 16

a = 16/8 = 2

4b = 4-8a = 4-8(2) = 4-16 = -12

b = -12/4 = -3

T6 = a6² + 6b

T6 = 2(36) + 6(-3) = 72 -18 = 54

7 0
2 years ago
Read 2 more answers
What is the intermediate step in the form (x+a)2 = b as a result of completing the square for the following x^2+16x-145=10x-7
Lorico [155]

Answer:

(x+3)^2=147

Step-by-step explanation:

7 0
3 years ago
How do you turn .33333333 into a fraction
Firlakuza [10]
3/1 i think
-----------------
7 0
3 years ago
List the next four multiples of fraction 7/12
Sidana [21]
<h2>Hello!</h2>

The answer is:

\frac{14}{12}=\frac{7}{12}*2\\\\\\\frac{21}{12}=\frac{7}{12}*3\\\\\\\\\frac{28}{12}=\frac{7}{12}*4\\\\\\\\\frac{35}{12}=\frac{7}{12}*5

<h2>Why?</h2>

A multiple of a number is the repeated sum of itself, for example:

Multiple of the number 1 are: 1, 2, 3, 4, 5 and so...

Multiple of the number 3 are: 3, 6, 9, 12, 15 and so...

From the example we have:

Multiple of the number 3 are: Itself, (3+3), (3+3+3), (3+3+3+3), (3+3+3+3+3) and so...

So,

Multiple of \frac{7}{12} are:

\frac{14}{12}=\frac{7}{12}*2=\frac{7}{12}+\frac{7}{12}\\\\\\\frac{21}{12}=\frac{7}{12}*3=\frac{7}{12}+\frac{7}{12}+\frac{7}{12}\\\\\\\\\frac{28}{12}=\frac{7}{12}*4=\frac{7}{12}+\frac{7}{12}+\frac{7}{12}+\frac{7}{12}\\\\\\\\\frac{35}{12}=\frac{7}{12}*5=\frac{7}{12}+\frac{7}{12}+\frac{7}{12}+\frac{7}{12}+\frac{7}{12}

Have a nice day!

6 0
3 years ago
What is the substitution of<br><img src="https://tex.z-dn.net/?f=%28x%20%20-%20%201%29%5E%7B2%7D%20" id="TexFormula1" title="(x
Ber [7]

Answer:

x should be 1

I think if you substitute it will just be the index 2 that remains , not sure though .You should probably ask your teacher for assistance

5 0
3 years ago
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