Answer:
Step-by-step explanation:
Perpendicular lines have negative reciprocal slopes. To find the line, convert the slope of q and substitute it with (6, -5) into point slope form.
y = 3x + 5 is q. It has a slope of 3. So p will have a slope of -1/3.
For a 30 sided regular polygon, We can divide the polygon (30 sides) into 30 inscribed triangles with central vertex angles of = 
.
This central vertex angle of <u>12 degrees</u> is the degree of rotation for a 30 sided polygon.
In other words, the 30 sided polygon has <u>12 degree</u> rotational symmetry about the center.
Answer:
2x+y=15x+y=10
Consider the first equation. Subtract 15x from both sides.
2x+y−15x=y
Combine 2x and −15x to get −13x.
−13x+y=y
Subtract y from both sides.
−13x+y−y=0
Combine y and −y to get 0.
−13x=0
Divide both sides by −13. Zero divided by any non-zero number gives zero.
x=0
Consider the second equation. Insert the known values of variables into the equation.
15×0+y=10
Multiply 15 and 0 to get 0.
0+y=10
Anything plus zero gives itself.
Answer:
A' is (1,1) B is (4,1) C is (1,-1)
Step-by-step explanation:
Since we rotating the figure about point a, we know a is the center of the rotation meaning no matter how far we rotate point a new image will stay on where point a pre image was which in this case is (1,1). Also since we know the rules of rotating a angle 90 degrees About the origin we are going to translate the figure to have the one point we are rotating about at the orgin. Since translations are a rigid transformations, the figure will stay the same A. Move the figure 1 to the left and 1 down so A becomes 0,0 B becomes 0,3 and C becomes 2,0. Then apply the rules of 90 degree clockwise rotation rules. (x,y) goes to (y,-x) . A stays (0,0) B becomes (3,0) and C becomes (0,-2). Then translate the figure 1 to the right and 1 down since we rotating about point a which is 1,1 and it at 0,0 rn. A' is 1,1. B' becomes (4,1). C' becomes (1,-1).
