(13x+14)(6x-5)=0
78x²-65x+84x-70=0
78x²+19x-70=0
It was equation.
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Factoring⇒ a×c=78×(-70)=-5460
84×(-65)=-5460
84+(-65)=19 which is b
__________________
78x²+84x-65x-70=0
6x(13x+14)-5(13x+14)=0
(13x+14)(6x-5)=0
13x+14=0 6x-5=0
13x=-14 6x=5
x=-14/13 x=5/6
Two solution X=-14/13;5/6
Answer:
Option b is the correct answer as both the equations are true for given solution.
Step-by-step explanation:
Given equations are:
-0.1x-0.3y=1.2
0.2x-0.5y=2
We can observe each graph and find the point that is the solution and put the point in the equations to know if that point is the solution
<u>For option A:</u>
(0,4)
Putting x=0 and y = 4 in both equations

This is not the correct answer as both equations are not true with this solution
<u>For Option B:</u>
(0,-4)
Putting x = 0 and y = -4 in both equations

Both equations are true for (0,-4) hence it is the solution of the system.
<u>For Option C:</u>
(4,0)

Not true for both equations
Hence,
Option b is the correct answer.
It would be O 945 that is the answer
3x + 2y = 39
5x - y = 13
Multiplying the last by two:
10x - 2y = 26
Adding to the first
13x = 65
x = 5
y = 5x-13 =25-13=12
Check:
3(5)+2(12)=39 good
5(5)-12=13 good
Answer: x=5, y=12
Given
mean of 406 grams and a standard deviation of 27 grams.
Find
The heaviest 14% of fruits weigh more than how many grams?
Explanation
given
mean = 406 gms
standard deviation = 27 gms
using standard normal table ,
![\begin{gathered} P(Z>z)=14\% \\ 1-P(Zso , [tex]\begin{gathered} x=z\times\sigma+\mu \\ x=1.08\times27+406 \\ x=435.16 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20P%28Z%3Ez%29%3D14%5C%25%20%5C%5C%201-P%28Zso%20%2C%20%5Btex%5D%5Cbegin%7Bgathered%7D%20x%3Dz%5Ctimes%5Csigma%2B%5Cmu%20%5C%5C%20x%3D1.08%5Ctimes27%2B406%20%5C%5C%20x%3D435.16%20%5Cend%7Bgathered%7D)
Final Answer
Therefore , The heaviest 14% of fruits weigh more than 435.16 gms