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3 years ago

13

Number 39 I'm so stuck help plz

1 answer:

stellarik [79]3 years ago

6 0

39 seems very easy. Just add 2 to the number of blocks in square 6. That'll give you Square 7 and so on.

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James spent $(2y2 + 6). He bought notebooks that each cost $(y2 − 1).

CaHeK987 [17]

The expression to find the number of notebooks James bought would be written as:

Number of notebooks = total spent / cost per item

Number of notebooks = (2y^2 + 6) / <span>(y^2 − 1)

</span><span>If y = 3, then the number of notebooks bought would be:

</span>Number of notebooks = (2y^2 + 6) / (y^2 − 1)
Number of notebooks = (2(3)^2 + 6) / (3^2 − 1)
Number of notebooks = 3 pieces<span>
</span><span>
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7 0

3 years ago

What is the difference?<br><br> 10.22 – 3.651<br><br> The difference is _____

irinina [24]

Answer:

6.569

Step-by-step explanation:

10.22

-3.651

_______

6.569

I hope this helps!!!! Have a great day!!!

3 0

2 years ago

Read 2 more answers

Which shows how to solve the equation -4/5 x = 80 for x in one step

san4es73 [151]

Answer:

$- \frac{1}{100}$

Step-by-step explanation:

$- \frac{4}{5x} = 80 \\ - \frac{4}{80 } = 5x \\ x = - \frac{1}{100}$

8 0

1 year ago

15) Find the value of x in the given square<br> Area = 34 in

lyudmila [28]

Answer:

Area of a square is given by:

A = a2

where a = length of side

6 0

3 years ago

What is the equation of a quadratic function P with rational coefficients that

Phoenix [80]

Answer:

$P(x) = x^2-6x+58$

Step-by-step explanation:

Quadratic function is function of the form $P(x)=ax^2+bx+c$ where a, b and c are real numbers and $a\neq 0$

A number is said to be a rational number if it can be written in the form $\frac{u}{v}$ where u and v are integers and $v\neq 0$ .

A number is said to be a complex number if it can be written in the form u+iv where u and v are real numbers.

A number 'a' is said to be a zero of a function P(x) if $P(a)=0$

We know that if zero of a fraction is of form u+iv then its other zero is u-iv.

As 3+7i is a zero of the function, 3-7i is also its zero.

So, given equation is $\left ( x-(3-7i) \right )\left ( x-(3+7i) \right )$

$P(x)=\left ( x-(3-7i) \right )\left ( x-(3+7i) \right )\\=x^2-x(3+7i)-x(3-7i)+(3-7i)(3+7i)\\=x^2-3x-7ix-3x+7ix+9+49\\=x^2-6x+58$

4 0

3 years ago