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zheka24 [161]
3 years ago
13

Number 39 I'm so stuck help plz

Mathematics
1 answer:
stellarik [79]3 years ago
6 0
39 seems very easy. Just add 2 to the number of blocks in square 6. That'll give you Square 7 and so on.
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A thermos in the shape of a cylinder is filled to
bearhunter [10]
Volume of a cylinder=πr^2h
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8 0
3 years ago
8 star fruit cost $16. How many star fruit can you buy for $8?
kompoz [17]

Answer:

4 star fruit.

Step-by-step explanation:

16/8 = 2

each star fruit is 2 dollars

so 8/2 = 4

you can buy 4 star fruit for 8 dollars.

5 0
3 years ago
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If cos Θ = square root 2 over 2 and 3 pi over 2 < Θ < 2π, what are the values of sin Θ and tan Θ? sin Θ = square root 2 ov
densk [106]

Answer:

\huge\boxed{\sin\theta=-\dfrac{\sqrt2}{2};\ \tan\theta=-1}

Step-by-step explanation:

We have:

\\cos\theta=\dfrac{\sqrt2}{2},\ \dfrac{3\pi}{2}

For sine use:

\sin^2x+\cos^2x=1\to\sin^2x=1-\cos^2x

Substitute:

\sin^2\theta=1-\left(\dfrac{\sqrt2}{2}\right)^2\\\\\sin^2\theta=1-\dfrac{(\sqrt2)^2}{2^2}\\\\\sin^2\theta=1-\dfrac{2}{4}\\\\\sin^2\theta=\dfrac{4}{4}-\dfrac{2}{4}\\\\\sin^2\theta=\dfrac{4-2}{4}\\\\\sin^2\theta=\dfrac{2}{4}\to\sin\theta=\pm\sqrt{\dfrac{2}{4}}\\\\\sin\theta=\pm\dfrac{\sqrt2}{\sqrt4}\\\\\sin\theta=\pm\dfrac{\sqrt2}{2}

θ in IV quadrant, therefore sine is negative.

\sin\theta=-\dfrac{\sqrt2}{2}

For tangent use:

\tan x=\dfrac{\sin x}{\cos x}

Substitute:

\tan\theta=\dfrac{-\frac{\sqrt2}{2}}{\frac{\sqrt2}{2}}=-\dfrac{\sqrt2}{2}\cdot\dfrac{2}{\sqrt2}=-1

8 0
3 years ago
You are selling tickets for the school play "13". Student tickets cost $4 and general admission tickets cost $6. You sell 525 ti
Scilla [17]

Answer:

Step-by-step explanation:

s= student ticket

g= general admisson ticket

4s+6g=2876

s+g=525

4s+6g=2876

-4s-4g=-2100

add both equations

2g=776

g=388

s+g=525

s+388=525

s=137

6 0
3 years ago
What is the LCM and GCF for 15 and 60
slavikrds [6]
LCM of 15 and 60 is 60.

GCF of 15 and 60 is 15.
7 0
3 years ago
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