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Marta_Voda [28]
2 years ago
14

Please help it’s geometry! I’ll make brainliest

Mathematics
2 answers:
Nitella [24]2 years ago
5 0
The second should be correct sorry if I’m wrong
expeople1 [14]2 years ago
4 0
GX is the angle bisector. Answer is C
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If an impulse travels 100 m/s, about how long will it take the impulse to travel 10 meters?
PtichkaEL [24]

Answer:

0.1 seconds

Step-by-step explanation:

10/100=0.1

6 0
2 years ago
Read 2 more answers
A water tanks can hold 234 cubic feet of water.How many gallons can the water tank hold
Veseljchak [2.6K]

1 cubic foot has 7.48 gallons of water.

Volume of water tank = 234 cubic feet

So, the number of gallons are = 234\times7.48=1750.32

Hence, the water tank can hold 1750.32 gallons of water.

4 0
3 years ago
PLEASE HELP!!! WILL MARK BRAINLIEST!!
slega [8]

Answer:

A

Step-by-step explanation:

I’m pretty sure since you’ve taken a cube from the original cube and relocated it, that means is not part of the surface area anymore.

I could be wrong tho lol

8 0
2 years ago
Read 2 more answers
Find the volume of the prism.<br> 9km 8km 6km
HACTEHA [7]

The correct answer is option B which is the volume of the prism is 216 km³.

<h3>What is the volume of the prism?</h3>

A prism is a three-dimensional solid with a triangular base called a triangular prism. The volume of the triangular prism is equal to the product of the area of the base and the height of the prism.

The volume of the prism will be calculated by using the formula below:-

V  =  Area of the base   x   Height

Since the base is a right-angle triangle so we will calculate the area of the right-angle triangle.

V  =  Area of the triangle  x  Height

V  =  ( 1/2 ) x 8 x 6 x ( 9 )

V  =  216 km²

Therefore the correct answer is option B which is the volume of the prism is 216 km³.

To know more about volume follow

brainly.com/question/1972490

#SPJ1

6 0
2 years ago
In the derivation of Newton’s method, to determine the formula for xi+1, the function f(x) is approximated using a first-order T
dimaraw [331]

Answer:

Part A.

Let f(x) = 0;

suppose x= a+h

such that f(x) =f(a+h) = 0

By second order Taylor approximation, we get

f(a) + hf'±(a) + \frac{h^{2} }{2!}f''(a) = 0

h = \frac{-f'(a) }{f''(a)} ± \frac{\sqrt[]{(f'(a))^{2}-2f(a)f''(a) } }{f''(a)}

So, we get the succeeding equation for Newton's method as

x_{i+1} = x_{i} + \frac{1}{f''x_{i}}  [-f'(x_{i}) ± \sqrt{f(x_{i})^{2}-2fx_{i}f''x_{i} } ]

Part B.

It is evident that Newton's method fails in two cases, as:

1.  if f''(x) = 0

2. if f'(x)² is less than 2f(x)f''(x)    

Part C.

In case  x_{i+1} is close to x_{i}, the choice that shouldbe made instead of ± in part A is:

f'(x) = \sqrt{f'(x)^{2} - 2f(x)f''(x)}  ⇔ x_{i+1} = x_{i}

Part D.

As given x_{i+1} = x_{i} = h

or                 h = x_{i+1} - x_{i}

We get,

f(a) + hf'(a) +(h²/2)f''(a) = 0

or h² = -hf(a)/f'(a)

Also,             (x_{i+1}-x_{i})² = -(x_{i+1}-x_{i})(f(x_{i})/f'(x_{i}))

So,                f(a) + hf'(a) - (f''(a)/2)(hf(a)/f'(a)) = 0

It becomes   h = -f(a)/f'(a) + (h/2)[f''(a)f(a)/(f(a))²]

Also,             x_{i+1} = x_{i} -f(x_{i})/f'(x_{i}) + [(x_{i+1} - x_{i})f''(x_{i})f(x_{i})]/[2(f'(x_{i}))²]

6 0
3 years ago
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