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ExtremeBDS [4]
3 years ago
12

The hanger image below represents a balanced equation.

Mathematics
2 answers:
cricket20 [7]3 years ago
5 0

Answer:

\frac{1}{5}  + z =  \frac{3}{5}

balu736 [363]3 years ago
5 0

Answer:

1/5+z=3/5

Step-by-step explanation:

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What is the cosine of angle F <br><br>A. 4/5<br>B. 3/4<br>C. 5/4<br>D. 3/5​
saveliy_v [14]

Answer: option D

Step-by-step explanation:

Remember the cosine identity:

cos\alpha=\frac{adjacent}{hypotenuse}

Given the right triangle DFE shown in the image, you can identify that the adjacent side and the hypotenuse for the angle F of this triangle are:

adjacent=15\\hypotenuse=25

Now you can substitute values into  cos\alpha=\frac{adjacent}{hypotenuse} and then reduce the fraction.

THerefore you get:cos(F)=\frac{15}{25}\\\\cos(F)=\frac{3}{5}

6 0
3 years ago
Read 2 more answers
If 60 is increased by 10%, what is the new amount
mylen [45]
10 percent of 60 is 6. So 60+6= 66
4 0
4 years ago
Read 2 more answers
the perimeter of a rectangle is 60 meters. if the length of the rectangle is 14 meters. what is the width of the rectangle.,
Ray Of Light [21]
Perimeter is 2width+2length
Therefore since you already know that the perimeter is 60 and the length is 14 you can set up the equation; 
60= 2w+14
with this you then need to find w so;
60=2w+14
-14     -14
46=2w
(46/2)=(2w/2)
13=w
The width is 13
8 0
3 years ago
Read 2 more answers
Please answer this in two minutes
solniwko [45]

Answer:

30

Step-by-step explanation:

a^2 + b^2 = c^2

(8sqrt(3))^2 + b^2 = 16^2

64 * 3 + b^2 = 256

192 + b^2 = 256

b^2 = 64

b = 8

The ratio of the lengths of the sides of this triangle is

8 : 8sqrt(3) : 16

which reduces to

1 : sqrt(3) : 2

This is the ratio of the lengths of the sides of a 30-60-90 triangle.

m<W = 30 deg

5 0
3 years ago
12x^3-11x^2+9x+18 divided by 4x+3
atroni [7]
12x^3-11x^2+9x+18 divided by 4x+3

put he division into fraction

12x^3-11x^2+9x+18/4 x +3

reduced fraction by 2

12x^3-11x^2+9x+9/2 x +3

calculate sum

12x^3-11x^2+27/2 x +3
that is your answer ^

hope this helps :)
3 0
3 years ago
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