Answer:
can you please make the question more clear!
Step-by-step explanation:
i am guessing you are asking if 1/ (2·2) (3+(3.4·5))=
1/ 4+17+3
1/24?
The value of p+q = 403,For the given complex number a+bi and
where p and q are co-primes
F(z)= (a+ib)z⇒this is equidistant from "0" and "z"
Given modulus of complex number (a+ib) = 10 ;
p and q ∈Z
G.C.D of ( p and q)=1
(a+ib)z equidistant from "0" and "z"


p = 399 and q= 4
p+q= 399+4
p+q=403
Hence the value of p+q = 403
Complete question:A function f is defined on the complex number by f (z) = (a + bi)z, where 'a' and 'b' are positive numbers. This function has the property that the image of each point in the complex plane is equidistant from that point and the origin. Given that |a+bi|=8 and that
where p and q are coprime. Find the value of (p+q)
Learn more about complex numbers here:
brainly.com/question/20566728
#SPJ4
Answer:
Step-by-step explanation:
Y = x² - 2x + 5
x = -2
y = -2² -2(-2) + 5
y = 4 + 4 + 5 = 13
x = -1
y = -1² -2(-1) + 5
y = 1 + 2 + 5 = 8
x = 1
y = 1² -2(1) + 5
y = 1 - 2 + 5 = 4
x = 3
y = 3² -2(3) + 5
y = 9 - 6 + 5 = 8
x = 6
y = 6² -2(6) + 5
y = 36 - 12 + 5 = 29
There are 4 boys and 12 students in total. It would be 4/12, but if it was to be simplified, it would be 1/3. The probability of a boy being selected is 1/3.
Answer:

Step-by-step explanation:
The equation
is a <em>linear equation</em>. By definition, the independent term on this equation (that is, the number that is not being multiplied by
) is the <em>y-intercept</em>, which is a fancy way of saying "the point where the line crosses the y-axis".
By looking at the equation, we know that our y-intercept is <em>c. </em>By looking at the graph, we can see that the y-intercept is -3. Therefore,
and we get the complete version of our linear equation:

Now, looking at the graph we can see that the point
lies on the line of the equation, which means that the point is a solution to our equation. All we have to do is replace
and
by the values of the given point (which are
and
, respectively), and then solve for
:

And we are done!