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3 years ago

- 7 and 8 What’s the answer

Mathematics

1 answer:

kvv77 [185]3 years ago

3 0

Answer:

Step-by-step explanation:

8-7= 1

Hope this helps!

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Suppose you want to know the exact number of the people who voted for candidate. Would you rather look at the bar graph or at fr

IgorC [24]

I would rather look at a frequency table because the exact numbers would be shown and it could tell you by how much and how frequently they’re increasing . A bar graph could do the same , but sometimes they could be grouped so it wouldn’t tell you the exact number .

4 0

3 years ago

I need the steps for 26

Leona [35]

Answer:

K = 51

Step-by-step explanation:

Since the triangles are similar, the angles are the same measure.

<K = <F

We can find angle F since the angles of a triangle add to 180

D + G + F = 180

59+70 +F = 180

Combine like terms

129+F = 180

Subtract 129 from each side

129-129+F = 180-129

F = 51

K = F = 51

7 0

3 years ago

Read 2 more answers

How many solutions does the nonlinear system of equations graphed below have?

MakcuM [25]

Answer: 4

Step-by-step explanation: just did it myself

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3 years ago

Juan is making t-shirts to sell at a concert.

o-na [289]

Answer:

7 shirts

Step-by-step explanation:

The function for producing shirts is

f($) = 50 + 7.5(x), where x is the number of shirt

The function for selling shirts is

f($) = 15(x)

For there to be a profit, he must make more money selling the shirts than he spent on making the shirts

Therefore, 15(x) > 50 + 7.5(x)

15x > 50 + 7.5x

15x - 7.5x > 50

7.5x > 50

x > 6.67 shirts

To make a profit, Juan must sell at least 7 shirts

7 0

2 years ago

Two particles travel along the space curves r1(t) = t, t2, t3 r2(t) = 1 + 2t, 1 + 6t, 1 + 14t . Find the points at which their p

GuDViN [60]

Answer:

A) points at which paths intersect : (1,1,1) ; (2,4,8)

B) DNE

Step-by-step explanation:

A) To find the points in which the particle paths intersect, it is necessary to find the values of t for which the three components of both vectors are equal:

$t_1=1+2t_2\\\\t_1^2=1+6t_2\\\\t_1^3=1+14t_2$

you replace t1 from the first equation in the second equation:

$(1+2t_2)^2=1+6t_2\\\\1+4t_2+4t_2^2=1+6t_2\\\\4t_2^2-2t_2=0\\\\t_2(2t_2-1)=0\\\\t_2=0\\\\t_2=\frac{1}{2}$

Then, for t2 = 0 and t2=1/2 you obtain for t1:

$t_1=1+2(0)=1\\\\t_1=1+2(\frac{1}{2})=2$

Hence, for t1=1 and t2=0 the paths intersect. Furthermore, for t1=2 and t2=1/2 the paths also intersect.

The points at which the paths intersect are:

$r_1(1)=(1,1,1)=r_2(0)=(1,1,1)\\\\r_1(2)=(2,4,8)=r_2(\frac{1}{2})=(2,4,8)$

B) You have the following two trajectories of two independent particles:

$r_1(t)=(t,t^2,t^3)\\\\r_2(t)=(1+2t,1+6t,1+14t)$

To find the time in which the particles collide, it is necessary that both particles are in the same position on the same time. That is, each component of the vectors must coincide:

$t=1+2t\\\\t^2=1+6t\\\\t^3=1+14t$

From the first equation you have:

$t=1+2t\\\\t=-1$

This values does not have a physical meaning, then, the particle do not collide

answer: DNE

5 0

3 years ago