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sattari [20]
2 years ago
6

En que epoca aprendieron a trabaja el cobre y otros metales?

Chemistry
1 answer:
g100num [7]2 years ago
6 0
Maybe if you put it in english i’ll answer.. nahh jp i’m fluent
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Rank the following carboxylic acids from strongest (1) to weakest (4)
Paha777 [63]

Answer:

CH2FCOOH > CH2ClCOOH > CH2BrCOOH > CH3COOH

Explanation:

CH2FCOOH > CH2ClCOOH > CH2BrCOOH > CH3COOH

More electronegative atom of halogen is , stronger acid will be.

6 0
3 years ago
Calculate the internal energy of 2 moles of argon gas (assuming ideal behavior) at 298 K. Suggest two ways to increase its inter
Dominik [7]
I hope this helps you.

5 0
3 years ago
Any change that alters a substance without changing it into another substance.
Ber [7]
A physical change.

Physical change = can be reverted + doesn't change substance
Chemical = changes substance
7 0
3 years ago
Which corresponds to the composition of the ion typically formed by magnesium?
nekit [7.7K]
The ion composition of Magnesium is 12,10, 2+.
Magnesium is a chemical element with symbol Mg and an atomic number 12, it has 12 protons, and 12 electrons with a chemical configuration of 2:8:2. It requires to loose two electrons to form a stable configuration forming a cation (positively charged ion) with a charge of +2 and  a configuration of 2:8 ( 12 protons and 10 electrons).
3 0
3 years ago
3. In an experiment it was found that 40.0cm of 0.2M sodium hydroxide solution just neutralized 0.2g
hjlf

The relative molecular mass of acid A : 50 g/mol

<h3>Further explanation</h3>

Given

40.0 cm³(40 ml) of 0.2M sodium hydroxide

0.2g  of a dibasic acid

Required

the relative molecular mass of acid A

Solution

Titration formula

M₁V₁n₁=M₂V₂n₂

n=acid/base valence(number of H⁺/OH⁻)

NaOH ⇒ n = 1

Dibasic acid =  diprotic acid (such as H₂SO₄)⇒ n = 2

mol = M x V

Input the value in the formula :(1 = NaOH, 2=dibasic acid)

0.2 x 40 x 1 = M₂ x V₂ x 2

M₂ x V₂ = 4 mlmol = 4.10⁻³ mol ⇒ mol of Acid A

The relative molecular mass of acid A (M) :

\tt M_A=\dfrac{mass }{mol}=\dfrac{0.2~g}{4.10^{-3}}=50~g/mol

5 0
3 years ago
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