Explanation:
Compound A:
Mass of sulphur = 0.603g
Mass of Palladium = 0.397g
0.603g of sulphur combine with 0.397g of Palladium.
Therefore, 1g of sulphur will combine with = 0.397 / 0.603 = 0.658g of Palladium
Compound B:
Mass of sulphur = 0.301g
Mass of Palladium = 0.699
0.301g of sulphur combine with 0.699g of Palladium. Therefore, 1g of sulphur will combine with
= 0.699 / 0.301 = 2.322g of Palladium
Compound C:
Mass of sulphur = 0.151g
Mass of Palladium = 0.849g
0. 151g of sulphur combine with 0.849g of Palladium,
Therefore 1g of sulphur will combine with = 0.849/ 0.151 = 5.623g of Palladium
Therefore, the masses of Palladium which combine with a mixed mass (1g) of sulphur are in ratio
0.658 : 2.322 : 5.623 i.e 1: 4 : 9 which is a simple ratio
I would say A,B and D. The spectra allow for the determination of isotopic signatures of samples, the masses of particles and of molecules and thus the density, and most likely the energy levels of atoms. The energy given off by the elements allow these qualities and quantities to be determined.
The sp2 hybridized carbons have shorter and stronger bonds than the sp3 hybridized carbon atoms.
<h3>What is a dihalide?</h3>
A dihalide is an organic compound that contains two halogen atoms that are located on different carbon atoms hence they can be eliminated during dehydrohalogenation reactions.
We must note that it is more difficult to form an alkyne from a dihalide because the sp2 hybridized carbons have shorter and stronger bonds than the sp3 hybridized carbon atoms.
Learn more about sp2 hybridized carbons: brainly.com/question/6920150
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