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STatiana [176]
4 years ago
12

Suppose that water is pouring into a swimming pool in the shape of a right circular cylinder at a constant rate of 4 cubic feet

per minute. If the pool has radius 4 feet and height 10 feet, what is the rate of change of the height of the water in the pool when the depth of the water in the pool is 8 feet?
Mathematics
1 answer:
lesantik [10]4 years ago
5 0
Final answer is 49 \pi /5


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If one supplementary angle measure 51 degrees the other angle measures 39 degrees?
mojhsa [17]
The answer to your question is false
7 0
3 years ago
A museum sold 95 tickets for $1,025. Each adult ticket was $15, and each child ticket was $7. Let a represent the number of adul
Genrish500 [490]

Answer:

a + c = 95........eq1

15a + 7c = 1,025....eq2

Step-by-step explanation:

Given:

Total number of ticket sold = 95

Total amount collected = $1,025

Price of each adult ticket = $15

Price of each child ticket = $7

Computation:

Number of adult tickets sold = a

Number of child tickets sold = c

So,

Number of adult tickets sold + Number of child tickets sold = Total number of ticket sold

a + c = 95........eq1

and

15a + 7c = 1,025....eq2

4 0
3 years ago
The top of a round table is 4 feet in diameter. The top splits to allow two extra boards to be inserted. The expansion boards ar
Nutka1998 [239]
The answer will be 6
8 0
4 years ago
Yahoo creates a test to classify emails as spam or not spam based on the contained words. This test accurately identifies spam (
Amiraneli [1.4K]

Answer and Step-by-step explanation:

The computation is shown below:

Let us assume that

Spam Email be S

And, test spam positive be T

Given that

P(S) = 0.3

P(\frac{T}{S}) = 0.95

P(\frac{T}{S^c}) = 0.05

Now based on the above information, the probabilities are as follows

i. P(Spam Email) is

= P(S)

= 0.3

P(S^c) =  1 - P(S)

= 1 - 0.3

= 0.7

ii. P(\frac{S}{T}) = \frac{P(S\cap\ T}{P(T)}

= \frac{P(\frac{T}{S}) . P(S) }{P(\frac{T}{S}) . P(S) + P(\frac{T}{S^c}) . P(S^c) }

= \frac{0.95 \times 0.3}{0.95 \times 0.3 + 0.05 \times 0.7}

= 0.8906

iii. P(\frac{S}{T^c}) = \frac{P(S\cap\ T^c}{P(T^c)}

= \frac{P(\frac{T^c}{S}) . P(S) }{P(\frac{T^c}{S}) . P(S) + P(\frac{T^c}{S^c}) . P(S^c) }

= \frac{(1 - 0.95)\times 0.3}{ (1 -0.95)0.95 \times 0.3 + (1 - 0.05) \times 0.7}

= 0.0221

We simply applied the above formulas so that the each part could come

8 0
3 years ago
Sam scored 43, 48, and 42 points on three tests. How many points should he get on the fourth test to get an average score of 50?
tatiyna

So we know that an average is the sum of the scores divided by the number of scores that were added together. In this case we are going to be dealing with 4 tests. So let's say x is the score for our fourth test. We can create this equation:

\frac{x+43+48+42}{4}=50

So then we need to simplify the top:

\frac{x+133}{4}=50

Then multiply by 4 on both sides to get rid of the denominator:

x+133=200

Then solve for x:

x=67

So now we know that Sam needs to score a 67 on the fourth test to have an average score of 50.

6 0
3 years ago
Read 2 more answers
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