Step 1
Find the area of one equilateral triangle
Applying the law of sines
in this problem
a=b=7 cm
C=60 degrees
so
cm²
Step 2
To calculate the area of the hexagon multiply the area of one equilateral triangle by 
![Area Hexagon=6*[49*\frac{\sqrt{3}}{4}] \\ Area Hexagon=73.5*\sqrt{3}](https://tex.z-dn.net/?f=%20Area%20Hexagon%3D6%2A%5B49%2A%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B4%7D%5D%20%20%5C%5C%20Area%20Hexagon%3D73.5%2A%5Csqrt%7B3%7D%20%20)
cm²
therefore
the answer is the option
73.5 sqrt 3cm²
Answer:
1.4*40=56cm, DVD’s he has
1.4*3=4.2cm
56+4.2=60.2cm, whoops too much. So instead 1.4*2= 2.8cm, 56+2.8=58.8cm Is Your Answer.
First you find the area of the front face 1/2bh or in you case 10x12=120 1/2 of 120 is 60 next you multiply 60 by 20 to get 1,200 for the voulume
Answer:
I’m not really sure
Step-by-step explanation:
Look at someone else’s answer
Answer:
8a+9
Step-by-step explanation:
You have to add the like terms.
4.5a+7+3.5a+2
4.5a+3.5a=8a
7+2= 9
8a+9
